Answer:
-x^2 - 11x -30
Step-by-step explanation:
Solve using foiling. Ignore the -1 to begin with and just look at the part in parenthesis. Do x from the first parenthesis times the stuff in the second parenthesis.
ie: x(x) and x(6)
ie: x^2 + 6x
Then do the 5 times the things in the second parenthesis.
ie: 5(x) and 5(6)
ie: 5x + 30
Then add what you got from multiplying the first value to what you got from multiplying the second.
ie: x^2 + 11x + 30
This is a trinomial because it has three different variables. Now change all the signs to negative because of the -1 out front.
ie: -x^2 - 11x -30
D is 32
Bc of the alternate angle thing I don’t remember what it’s called
Anddd
For B
180-138= 42=42+29=71
180-71=109
Therefore a is 109
32 +20 is 52
180-52 =128
Answer:
<em>Multiply the bottom equation by -3/2 then add the equations.
</em>
<em>Multiply the top equation by-3. then add the equations
</em>
<em>
</em>
Step-by-step explanation:
Given the simultaneous equation
2x- 6y=6 ... 1
6x - 4y = 2 ... 2
To eliminate a variable, we have to make the coefficient of one of the variable to be the same.
Multiply equastion 1 by -3
-6x+18y= -18
6x - 4y = 2
Add the result:
-6x + 6x + 18y-4y = -18+2
18y-4y = -18+2
14y = -18
y = -9/7
Another way is to Multiply the bottom equation by -3/2 then add the equations.
Multiplying equation 2 by -3/2 will give;
6x(-3/2) - 4y(-3/2) = 2(-3/2)
-9x + 6y = -3
Add to equation 1;
2x- 6y=6
-9x + 2x + 0 = -3+6
-7x = 3
x = -3/7
Hence the correct two options are;
<em>Multiply the bottom equation by -3/2 then add the equations.
</em>
<em>Multiply the top equation by-3. then add the equations
</em>
<em>
</em>
<em></em>
<em></em>
Answer:
just doing this for points
Step-by-step explanation:
so ya :)
Answer: f(x)=2-x^2
Step-by-step explanation:
The quadratic equation is
y=ax^2+bx+c
and c is equal to the y-intercept.
in the twi graphs shown both have the same shape but different y-intervepts.
c(the y-intercept) in the first graph is 5 and in the second graph(F) is 2.
