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Artyom0805 [142]
3 years ago
14

Rx-st=r solve equation for s

Mathematics
2 answers:
dimulka [17.4K]3 years ago
8 0

Rx - st = r

Rx = r + st                                       Add st to both sides

Rx - r = st                                        Subtract r from both sides

(Rx - r)/t = s                                     Divide t on both sides ( to isolate s)

mafiozo [28]3 years ago
5 0

rx-st=r\qquad\text{subtract rx from both sides}\\\\-st=-rx+r\qquad\text{change the signs}\\\\st=rx-r\qquad\text{divide both sides by}\ t\neq0\\\\\boxed{s=\dfrac{rx-r}{t}}

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When solving -1/8(x+35)=-7 , what is the correct sequence of operations
TiliK225 [7]

x= -623/18

Hope it helps for you,buddy!


6 0
4 years ago
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Find the slope of the line through each pair of points.<br> (2, -4), (5,-8)
slega [8]

Answer:

m=-\frac{4}{3}

Step-by-step explanation:

Slope=m=\frac{y_2-y_1}{x_2-x_1}

Here

(x_1, y_1)=(2, -4) \ \ and \ \  (x_2, y_2)=(5, -8)

m=\frac{-8-(-4)}{5-2}

m=-\frac{4}{3}

8 0
3 years ago
What pattern do you notice in the numbers below? 1 = 1 × 1, and 1 × 1 × 1, and 1 × 1 × 1 64 = 8 × 8, and 4 × 4 × 4 729 = 27 × 27
11111nata11111 [884]

Answer:

<h3>C. They are both perfect squares and perfect cubes.</h3>

Step-by-step explanation:

Perfect squares are numbers that their square root can be found easily without any remainder.

Given the following patterns;

1*1 = 1  and 1*1*1 = 1

It can be seen that 1 is 1 perfect square since 1*1 = 1² = 1

Also 1 is perfect cube since 1*1*1 = 1³ = 1 (cube of the value gives 1)

Similarly for the expression;

8*8 = 64

8² = 64 (since the square of 8 gives 64, then 64 is known to be a perfect square)

Also 4*4*4 = 64

i.e 4³ = 64 (This shows that the cube root of 64 is 4 making it a perfect cube since we can get a whole number for the cube root of 64)

The same is applicable for other expressions 729 = 27 × 27, and 9 × 9 × 9, 4,096 = 64 × 64, and 16 × 16 × 16

This values are easily expressed as a constant multiple of a number showing that they are both perfect squares and perfect cubes.

4 0
3 years ago
A car travels at a constant speed.
ad-work [718]

Answer:

see below

Step-by-step explanation:

<h3>Given</h3>
  • Distance is 142.2 m, correct to 1 decimal place
  • Time is 7 seconds,  correct to nearest second
<h3>To find:</h3>
  • Upper bound for the speed
<h3>Solution </h3>

<em>Upper bound for the speed  = upper bound for distance/lower bound for time</em>

  • Upper bound for distance = 142.25 m  (added 0.1/5 = 0.05)
  • Lower bound for time = 6.5 seconds  (subtracted 1/2 = 0.5)

<u>Then, the speed is:</u>

  • 142.25/6.5 = 21.88 m/s
  • 21.88 = 21.9 m/s correct to 1 decimal place
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4 0
3 years ago
Please Help Best answer gets brainliest first answer gets five stars
Brrunno [24]

Hi,

(1/4)^−2−(5^0)(2)(1^−1)

=16−(5^0)(2)(1^−1)

=16−(1)(2)(1^−1)

=16−2(1^−1)

=16−(2)(1)

=16−2

=14

Have a great day!

4 0
4 years ago
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