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Step2247 [10]
3 years ago
5

Whats a story that can be solved using the equation 18.50 ÷ 0.5=x?

Mathematics
1 answer:
Solnce55 [7]3 years ago
4 0

Equation:

18.50 * 0.5 = x

18.50 * 0.5 = 9.25


Story:

John went to a store to buy a frying pan. He found the one he liked, and looked at the price. It was at 18.50 dollars. The next day, John went to the store to buy his pan, and saw that beside the price, there was something saying 50% off.

Write an equation that gives the final price of the pan.


Hope it helped,


BioTeacher101


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Daniel [21]

\huge \mathfrak \blue{Solution \:  - }

The formula for area of triangle is -

\frac{1}{2}   \times base \times height

________________________________

So, the area of first triangle =

\frac{1}{2}  \times base \:  \times height

\frac{1}{2}  \times 4  \times 3

=  \pink{6  \: units}

________________________________

Area of second triangle =

\frac{1}{2 }  \times base \times height

\frac{1}{2}  \times 4 \times 6

=  \pink {12 \:  units}

________________________________

Area of second triangle - Area of first triangle

= 12 - 6

= 6

\sf \underline\purple{The \: area \: increases \: by \: 6 \: square \: units.}

3 0
3 years ago
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Six teachers shared a box of paper equally. How many sheets of paper did each teacher get if 1,347 sheets of paper came in the b
tester [92]

Answer: 224.5

Step-by-step explanation:

The answer is 224.5 because 1347 divided by 6 is 224.5.

4 0
3 years ago
The angles in a triangle have<br><br> measures of 61°, (3z), (z-5)<br><br> What is the value of z?
vfiekz [6]

Answer:

z = 31

Step-by-step explanation:

A triangle adds up to 180 degrees

Therefore this equation is formed: 61 + 3z + z -5 = 180

Simplify:

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3 years ago
Find the expansion of cos x about the point x=0
ycow [4]

Answer:

Cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{1!} + ...

Step-by-step explanation:

We use Taylor series expansion to answer this question.

We have to find the expansion of cos x at x = 0

f(x) = cos x, f'(x) = -sin x, f''(x) = -cos x, f'''(x) = sin x, f''''(x) = cos x

Now we evaluate them at x = 0.

f(0) = 1, f'(0) = 0, f''(0) = -1, f'''(0) = 0, f''''(0) = 1

Now, by Taylor series expansion we have

f(x) = f(a) + f'(a)(x-a) + \frac{f''(a)(x-a)^2}{2!} + \frac{f'''(a)(x-a)^3}{3!} + \frac{f''''(a)(x-a)^4}{4!} + ...

Putting a = 0 and all the values from above in the expansion, we get,

Cos x = 1 - \frac{x^2}{2!} + \frac{x^4}{4!} - \frac{x^6}{1!} + ...

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3 years ago
3:5 as a ladder methed​
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Step-by-step explanation:

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