Answer:
The amount of fence needed to surround the mentioned space is:
Step-by-step explanation:
To identify the amount of fence, you must take all the measurements given in the exercise:
- Pool width = 20 ft
- Pool length = 40 ft
- Aditional area in each side = 10 ft
As each side has 10 additional feet, that is the lounge area, you must add 20 feet to each side of the pool, this is because, in the case of the width, you must add 10 feet to the right side and 10 feet to the left side, in the case of the length, you must add to each side 10 feet to the upper part and 10 feet to the lower part, in this form, the measurements of the fence must be:
- Width of fenced area = 40 ft
- Length of fenced area = 60 ft
As you know, the length has two sides and the length has two sides too, by this reason, we must multiply each value by 2 to obtain the amount of fence to all four sides of the lounge area:
- Amount of fence = 2(40 ft) + 2(60 ft)
- Amount of fence = 80 ft + 120 ft
- <u>Amount of fence = 200 ft</u>
As you can see, <u><em>the amount of fence needed to go around the lounge area is 200 feet</em></u>.
12*5*4.25=255 cubic in (total vol.)
.25*.25*.25=1/64 (vol. of small cube)
255/(1/64)=16,320 cubes
Since the congruent operator is ≅ and since AD is congruent to BD, I'm going to assume that you want to prove that AD is congruent to BD.
1. DE is equal to CD by definition since D is the midpoint of CE.
2. AE is equal to BC since opposite sides of a rectangle are equal to each other.
3. Angle AEC is equal to Angle BCE since all angles in a rectangle are right angles and all right angles are equal to each other.
4. Triangles ADE and BDC are congruent to each other because we have SAS congruence for both triangles.
5. AD is congruent to BC since they're corresponding sides of congruent triangles.
(2,0,-1,-1,-2) that is the domain from what I remember. Hope that help
Answer:
6 $1 bills, 5 $5 bills
Step-by-step explanation:
Say the student has x $1 bills.
Then they have 11 - x $5 bills.
31 = 1 * x + (11 - x) * 5 = 55 - 4x
4x = 55 - 31 = 24
x = 6
So, they have 6 $1 bills and 11 - 6 = 5 $5 bills
