If the perimeter of equilateral triangle is 77 and the equation showing the perimeter is 6.5X-1 then the value of X is equal to 12.
Given that the perimeter of equilateral triangle is 77 and the expression showing the perimeter is 6.5X-1.
We are required to find the value of X which is used in the expression.
Expression is combination of numbers, fraction, coefficients, indeterminants, determinants, which are mostly not found in equal to form.
Perimeter which is given is 77 and 6.5X-1.
6.5X-1=77
6.5X=77+1
6.5X=78
X=78/6.5
X=12
Hence if the perimeter of equilateral triangle is 77 and the expression showing the perimeter is 6.5X-1 then the value of X is equal to 12.
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Answer:
(-1, 1), (-1, 4), and (1, 4) are the vertices of a right triangle.
Step-by-step explanation:
If you were to graph these three points on a coordinate plane, you'll notice that two of the sides form a right angle together, which means this triangle will be a right triangle. If you're looking for something more specific, it would be a right scalene triangle, where all sides are different in a right triangle.
0.002, 0.02, 0.05 (which is 1/20), 0.2
Because you're trying to make them congruent, equal the two expressions to each other.
So, for #10 you would equal them so it would look like this.
2x+2=5x-19
Then you would just go ahead and simplify
2x+2=5x-19
-2x -2x
---------------
2= 3x -19
+19 +19
---------------
21=3x
--- ----
3 3
x=7
This means that x should be 7. You can check this just by plugging it in
2x+2
2(7)+2 = 16
5x-19
5(7)-19= 16
Same with #11.
x+8=3x-14
-x -x
--------------
8=2x-14
+14 +14
--------------
22=2x
--- ----
2 2
x=11
Check.
x+8
11+8= 19
3x-14
3(11) - 14 = 19
