Let us use the formula with the point (4,5) and (0,2)
![\begin{gathered} d=\sqrt[]{(x_1-x_2)^2+(y_1-y_2)^2}=\sqrt[]{(4-0)^2+(5-2)^2} \\ =\sqrt[]{16+9}=\sqrt[]{25}=5 \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20d%3D%5Csqrt%5B%5D%7B%28x_1-x_2%29%5E2%2B%28y_1-y_2%29%5E2%7D%3D%5Csqrt%5B%5D%7B%284-0%29%5E2%2B%285-2%29%5E2%7D%20%5C%5C%20%3D%5Csqrt%5B%5D%7B16%2B9%7D%3D%5Csqrt%5B%5D%7B25%7D%3D5%20%5Cend%7Bgathered%7D)
Answer:
Step-by-step explanation:
So the two lines before and after the expression means absolute value, or modulus of, knowing this, it means that the answer must always yield positive. So if x-6 is positive, it will stay positive, if x-6 is negative, it will turn positive, therefore it can never yield a negative value.
Now im assuming the second question is meant to be absolute value of x-5 is less than 0, because it makes no sense otherwise.
So now knowing that x-5 is always positive, or 0, but this inequality only wants less than 0, this means there are no solutions for the inequality.
I think it's B. not sure though u should wait. till someone else answer to see if I am right
