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Aloiza [94]
3 years ago
7

Pls help me. will give brainliest if correct!!

Mathematics
1 answer:
baherus [9]3 years ago
6 0
The answer is 12.206556

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C≈37.7

Step-by-step explanation:

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Solve for x: 3-(2x-5)<-4(x+2)
andriy [413]
3-(2x-5)<-4(x+2)

8-2x<-8-4x

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3 0
3 years ago
What is the value of x? Thanks for the help
-BARSIC- [3]
Hello! I can help you! First things first, because they are both the same angles on opposite sides, let's set this up in the form of an equation and solve for "x". It would be set up like this:

2x + 20 = 3x - 30

You see up top that it says 2(x + 10). What you would do is multiply what's in the parenthesis by 2, in order to get 2x + 20. Then put the equal sign and write 3x - 30. Subtract 3x from both sides to get -1x + 20 = -30. Subtract 20 from both sides to get -1x = -50. Divide each side by -1 to isolate the "x". In this case, because you are dividing a negative number by a negative number, your quotient will be positive. -50/-1 is 50. Let's plug in the value as "x" and see if it works. 50 * 2 is 100. 100 + 20 is 120. 50 * 3 is 150. 150 - 30 is 120. 120 = 120. There. x = 50.
8 0
3 years ago
Plz help me!!!
Nadya [2.5K]
To solve this we are going to use the exponential function: f(t)=a(1(+/-)b)^t
where
f(t) is the final amount after t years
a is the initial amount
b is the decay  or grow rate rate in decimal form
t is the time in years

Expression A 
f(t)=624(0.95)^{4t}
Since the base (0.95) is less than one, we have a decay rate here.
Now to find the rate b, we are going to use the formula: b=|1-base|*100%
b=|1-0.95|*100%
b=0.05*100%
b=5%
We can conclude that expression A decays at a rate of 5% every three months.

Now, to find the initial value of the function, we are going to evaluate the function at t=0
f(t)=624(0.95)^{4t}
f(0)=624(0.95)^{0t}
f(0)=624(0.95)^{0}
f(0)=624(1)
f(0)=624
We can conclude that the initial value of expression A is 624.

Expression B
f(t)=725(1.12)^{3t}
Since the base (1.12) is greater than 1, we have a growth rate here.
To find the rate, we are going to use the same equation as before:
b=|1-base|*100%
b=|1-1.12|*100
b=|-0.12|*100%
b=0.12*100%
b=12%
We can conclude that expression B grows at a rate of 12% every 4 months.

Just like before, to find the initial value of the expression, we are going to evaluate it at t=0
f(t)=725(1.12)^{3t}
f(0)=725(1.12)^{0t}
f(0)=725(1.12)^{0}
f(0)=725(1)
f(0)=725
The initial value of expression B is 725.

We can conclude that you should select the statements:
- Expression A decays at a rate of 5% every three months, while expression B grows at a rate of 12% every fourth months. 

- Expression A has an initial value of 624, while expression B has an initial value of 725.

8 0
2 years ago
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