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kkurt [141]
4 years ago
6

Use the Alternating Series Remainder Theorem to determine the smallest number of terms required to approximate the sum of the se

ries with an error of less than 0.001. [infinity] (−1)n + 1 n2 n = 1

Mathematics
1 answer:
Law Incorporation [45]4 years ago
6 0

Answer:

at N ≥ 6

Step-by-step explanation:

Error permissible = 0.001

The series = infinity  

at ( N + 1 ) ! > 1000  the inequality N ≥ 6 is valid and holds

attached below is the detailed solution using alternating series remainder

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What is the perimeter of this figure, to the nearest unit?
lana66690 [7]

Answer:

P=38

Step-by-step explanation:

At this case I would use the circumference formula for the rounded part.

The formula of the circumference is C=2πr.

So... We know that the radius is 5 which is half of the diameter. So... C=2π5 which is C=10π or C=31.4 which we divide by 4 because on the image is 1/4th of a circle and C/4 which C=7.85 so the P of the whole figure is P=10+10+5+5+7.85 which is P=37.85 which will be P=38.

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What is the slope of the line that passes through the points (-9, 10) and (-13, 13)?
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Step-by-step explanation:

4 0
3 years ago
Fairfield Homes is developing two parcels near Pigeon Fork, Tennessee. In order to test different advertising approaches, it use
evablogger [386]

Answer:

(1)  Null Hypothesis, H_0 : \mu_1 = \mu_2

    Alternate Hypothesis, H_1 : \mu_1\neq \mu_2

(2) Test statistics = -1.48

(3) At the 0.05 significance level, Fair field conclude that the population means are same.

Step-by-step explanation:

Let \mu_1 = mean annual family income for 12 people making inquiries at the first development

\mu_2 = mean annual family income for 24 people making inquiries at the second development

s_1 = standard deviation of annual family income for 12 people making inquiries at the first development

s_2 = standard deviation of annual family income for 24 people making inquiries at the second development

n_1 = sample of people of first development i.e. 12

n_2 = sample of people of second development i.e. 24

(1) Null Hypothesis, H_0 : \mu_1 = \mu_2  {population means are same}

  Alternate Hypothesis, H_1 : \mu_1\neq \mu_2  {population means are different}

<u>DECISION RULE ;</u>

  • If the test statistics is less than the critical value of t from table at 5% significance level, then we will accept null hypothesis, H_0 .
  • If the test statistics is more than the critical value of t from table at 5% significance level, then we will reject null hypothesis, H_0 .

(2) The test statistics is given by;

                      \frac{(X_1bar -X_2bar) - (\mu_1-\mu_2)}{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}  } } ~ t_n__1+n_2-2

where,  X_1bar = Sample mean income of people at first development

                        = $153,000

X_2bar = Sample mean income of people at second development = $171,000  

s_1 = $42,000  and   s_2 = $30,000

   s_p= \sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2}  }{n_1+n_2-2}} =  \sqrt{\frac{(12-1)42000^{2}+(24-1)30000^{2}  }{12+24-2}} = 34344.30

Test statistics = \frac{(153000 -171000) - 0}{34344.30\sqrt{\frac{1}{12}+\frac{1}{24}  } } ~ t_3_4

                       = -1.48

(3) At 5% level of significance, t table gives critical value of 2.032 at 34 degree of freedom.Since our test statistics is less than the critical value of t so considering our decision rule, we will accept null hypothesis.

And conclude that population means are same.

4 0
4 years ago
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