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kkurt [141]
3 years ago
6

Use the Alternating Series Remainder Theorem to determine the smallest number of terms required to approximate the sum of the se

ries with an error of less than 0.001. [infinity] (−1)n + 1 n2 n = 1

Mathematics
1 answer:
Law Incorporation [45]3 years ago
6 0

Answer:

at N ≥ 6

Step-by-step explanation:

Error permissible = 0.001

The series = infinity  

at ( N + 1 ) ! > 1000  the inequality N ≥ 6 is valid and holds

attached below is the detailed solution using alternating series remainder

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Point slope equations
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Answer:

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Step-by-step explanation:

To use this equation, you need to know:

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<u>First</u>:

(x1,y1) = a known point on the line

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<u>Now</u>:

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4 0
3 years ago
Simplify 5^3/5^7 leaving your anwser in index form
Wewaii [24]

Steps:

Simplify:

5³/5⁷

= 5³/5⁷

= 5*5*5/ 5*5*5*5*5*5*5

=1/5⁴

=1/625 (Decimal: 0.0016)

Steps by Step:

5³/5⁷

=125/5⁷

=125/78125

=1/625

Answer:   =1/625       (Decimal: 0.0016)

Please mark brainliest

<em><u>Hope this helps.</u></em>

6 0
3 years ago
Evaluate cos2 θ tan2 θ + tan2 θ sin2 θ in terms of tan θ.
Marianna [84]

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Step-by-step explanation:

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2 years ago
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Answer:

hope it helps

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
kirby often forgets to switch the inequity sign when dividing a negative. when solving 3x-10≥x, should kirby collect the variabl
sukhopar [10]
You should collect the variable on the left side since you can't have two variables of the same letter on each side.so you would take the variable from the right side and subtract it from the left. So subtract x on both sides. Your new problem is 2x-10 is greater than or equal to 0. Now you add 10 on both sides. Your new problem is 2x is greater than or equal to 10. Now divide by 2 on both sides. Your answer would be x is greater than or equal to 5
7 0
3 years ago
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