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3 years ago

What does 4/x+5 + 2x/x^2-25 equal?

1 answer:

8 0

Solve for x over the real numbers:
6/x - 20 = 0
Bring 6/x - 20 together using the common denominator x:
-(2 (10 x - 3))/x = 0
Divide both sides by -2:
(10 x - 3)/x = 0
Multiply both sides by x:
10 x - 3 = 0
Add 3 to both sides:
10 x = 3
Divide both sides by 10:
Answer: x = 3/10

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To the nearest millimeter, a cell phone is 72 mm long and 46 mm wide. What is the ratio of the width to the length

earnstyle [38]

Answer:

Length = 72 mm

Width = 46 mm

Ratio = 72:46 = 36:23

Step-by-step explanation:

72 and 36 both are divisible by 2. so when we divide them by two we get 36 and 23. we can divide both the sides only with the same number, but 36 and 23 have no common factors. so we leave it here and this is the answer.

5 0

3 years ago

What is 7/81 + 7/9 as a proper fraction

Lorico [155]

70/81 is 7/81+7/9 as a proper fraction

3 0

3 years ago

Describe the following graph. Use terms

timama [110]

I think it’s non-linear

3 0

3 years ago

Draw the graph of g(x) = 2x + 3, if x ≥ 1 g(x) = 5, if x > 1

trapecia [35]

G(x)=2x+3
x ≥ 1
g(x)=5
x is bigger then 1

6 0

3 years ago

The number and frequency of Atlantic hurricanes annually from 1940 through 2007 is shown here:

klio [65]

Answer:

The probability table is shown below.

A Poisson distribution can be used to approximate the model of the number of hurricanes each season.

Step-by-step explanation:

(a)

The formula to compute the probability of an event E is:

$P(E)=\frac{Favorable\ no.\ of\ frequencies}{Total\ NO.\ of\ frequencies}$

Use this formula to compute the probabilities of 0 - 8 hurricanes each season.

The table for the probabilities is shown below.

(b)

Compute the mean number of hurricanes per season as follows:

$E(X)=\frac{\sum x f_{x}}{\sum f_{x}}=\frac{176}{68}= 2.5882\approx2.59$

If the variable X follows a Poisson distribution with parameter λ = 7.56 then the probability function is:

$P(X=x)=\frac{e^{-2.59}(2.59)^{x}}{x!} ;\ x=0, 1, 2,...$

Compute the probability of X = 0 as follows:

$P(X=0)=\frac{e^{-2.59}(2.59)^{0}}{0!} =\frac{0.075\times1}{1}=0.075$

Compute the probability of X = 1 as follows:

$\neq P(X=1)=\frac{e^{-2.59}(2.59)^{1}}{1!} =\frac{0.075\times7.56}{1}=0.1943$

Compute the probabilities for the rest of the values of X in the similar way.

The probabilities are shown in the table.

On comparing the two probability tables, it can be seen that the Poisson distribution can be used to approximate the distribution of the number of hurricanes each season. This is because for every value of X the Poisson probability is approximately equal to the empirical probability.

5 0

3 years ago