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Ann [662]
3 years ago
11

Use rounding to determine if the following answers are reasonable. Round each of the factors to the nearest ten, then multiply.

Mathematics
1 answer:
Murrr4er [49]3 years ago
6 0

<u>A. 587 * 92</u>

We are rounding these factors to the nearest ten, so 587 becomes 590 and 92 becomes 90.

Now multiply 590 and 90.

590 * 90 = 53,100; 59 * 9 = 531, and then add on the two zeroes.

The following answer of 54,004 is reasonable because it is close to our estimate of 53,100.

<u>B. 117 * 19</u>

Rounding these numbers to the nearest ten, you make 117 become 120 and 19 become 20.

Multiply 120 and 20.

120 * 20 = 2,400; I multiplied 12 and 2 to get 24, then added on the two zeroes.

The following answer of 222.3 is not reasonable because it is way off from 2,400. They are about 1,200 apart.

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Translate and solve: Three more than the difference of 6s and 5s is equal to the difference of 1/12 and 1/6
PilotLPTM [1.2K]

Answer:

a. (6s-5s)+3=\frac{1}{12}-\frac{1}{6}

b. s=-\frac{37}{12}

Step-by-step explanation:

You need to remember that:

1. The word "more" indicates Addition.

2. The "Difference" is the result of a Subtraction.

a. Then, knowing this information, you know that:

- "The difference of 6s and 5s" must be expressed as:

6s-5s

- Then, "Three more than the difference of 6s and 5s " is:

(6s-5s)+3

- "The difference of  \frac{1}{12} and \frac{1}{6} " can be expressed in this form:

\frac{1}{12}-\frac{1}{6}

Therefore, "Three more than the difference of 6s and 5s is equal to the difference of  \frac{1}{12} and \frac{1}{6} " is:

(6s-5s)+3=\frac{1}{12}-\frac{1}{6}

b. Solve for "s" in order to find its value:

s+3=-\frac{1}{12}\\\\12(s+3)=-1\\\\12s+36=-1\\\\12s=-1-36\\\\s=-\frac{37}{12}

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