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Ann [662]
3 years ago
11

Use rounding to determine if the following answers are reasonable. Round each of the factors to the nearest ten, then multiply.

Mathematics
1 answer:
Murrr4er [49]3 years ago
6 0

<u>A. 587 * 92</u>

We are rounding these factors to the nearest ten, so 587 becomes 590 and 92 becomes 90.

Now multiply 590 and 90.

590 * 90 = 53,100; 59 * 9 = 531, and then add on the two zeroes.

The following answer of 54,004 is reasonable because it is close to our estimate of 53,100.

<u>B. 117 * 19</u>

Rounding these numbers to the nearest ten, you make 117 become 120 and 19 become 20.

Multiply 120 and 20.

120 * 20 = 2,400; I multiplied 12 and 2 to get 24, then added on the two zeroes.

The following answer of 222.3 is not reasonable because it is way off from 2,400. They are about 1,200 apart.

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if one bucket + 5 jars equal one tub and three buckets plus two jars equal to tubs how many jars are there equal to one tub​
d1i1m1o1n [39]

Answer:

Simplify 4y + 7x = 2t and there you go that's your answer☺

Step-by-step explanation:

Bucket = y

Jars = x

Tubs = t

y + 5x = t

3y + 2x = t

5 0
3 years ago
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To safely cross a bridge, the most a delivery truck can weigh is 4 tons. The empty truck and driver weigh a total of 5,690 pound
brilliants [131]

Answer:

Truck can safely carry <em>2310 pounds </em> of cargo.

Step-by-step explanation:

Given the safety limit of weight to cross the bridge safely is 4 tons.

1 ton is equal to 2000 pounds.

so, 4 tons are equal to 2000 \times 4 = 8000 pounds

Now, given that

weight of empty truck and driver = 5690 pounds

To find:

Weight of cargo that the truck can safely carry ?

Solution:

Total weight of the truck is actually the combined weight of the empty truck, the drive and the cargo carried in it.

So, Total Weight allowed = 8000 pounds = 5690 pounds + Weight of Cargo

Weight of Cargo = 8000 - 5690 pounds

Weight of Cargo = <em>2310 pounds</em>

Truck can safely carry <em>2310 pounds </em> of cargo.

7 0
3 years ago
What is the measure of the corresponding central angle for XY in radians?
beks73 [17]

Answer:

4 radians

Step-by-step explanation:

Arc Length (Radians) = rθ

Given Arc Length XY  = 40cm and radius, r = 10cm,

we will substitute these 2 values into the formula to find θ.

(10)θ  = 40

θ = 40 / 10

= 4 radians

5 0
2 years ago
Read 2 more answers
A car rental company's standard charge includes an initial fee plus an additional fee for each mile driven. The standard charge
Radda [10]
4 days later. ugh haha sorry. answer in the first ten min on time my butt

7 0
3 years ago
Question 5 (5 points)
Tpy6a [65]

Answer:

The solution of the system of equations is, (1,-1,2)

Step-by-step explanation:

Given system equation;

x + 5y - 3z = -10

-5x + 6y – 5z = -21

-x + 8y - 8z = -25

Matrix form is written as;

\left[\begin{array}{ccc}1&5&-3\\-5&6&-5\\-1&8&-8\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}-10\\-21\\-25\end{array}\right] \\\\\\det. = 1\left[\begin{array}{cc}\\6&-5\\8&-8\end{array}\right] -5\left[\begin{array}{cc}\\-5&-5\\-1&-8\end{array}\right] -3\left[\begin{array}{cc}\\-5&6\\-1&8\end{array}\right] \\\\\\det. = 1(-8) -5(35)-3(-34)= -8 - 175+ 102 = -81

Cofactor;

First \ row \left[\begin{array}{cc}+\\ 6&-5\\\ 8&-8\end{array}\right  \left\begin{array}{cc}-\\ -5&-5\\-1&-8\end{array}\right \left\begin{array}{cc}+\\-5&6\\-1&8\end{array}\right] = [-8  \ \ -35 \ \ -34]\\\\\\\ Second \ row \left[\begin{array}{cc}-\\ 5&-3\\\ 8&-8\end{array}\right  \left\begin{array}{cc}+\\ 1&-3\\-1&-8\end{array}\right \left\begin{array}{cc}-\\1&5\\-1&8\end{array}\right]  = [16\ \ -11 \ \ -13]\\\\\\

Third \ row \left[\begin{array}{cc}+\\ 5&-3\\\ 6&-5\end{array}\right  \left\begin{array}{cc}-\\ 1&-3\\-5&-5\end{array}\right \left\begin{array}{cc}+\\1&5\\-5&6\end{array}\right]= [-7 \  \ 20\ \ 31]

Cofactor = \left[\begin{array}{ccc}-8&-35&-34\\16&-11&-13\\-7&20&31\end{array}\right]

inverse \ matrix =-\frac{1}{81}  \left[\begin{array}{ccc}-8&16&-7\\-35&-11&20\\-34&-13&31\end{array}\right] \\\\\\

Solution of the matrix:

\left[\begin{array}{c}x\\y\\z\end{array}\right] = -\frac{1}{81}  \left[\begin{array}{ccc}-8&16&-7\\-35&-11&20\\-34&-13&31\end{array}\right]  X \left[\begin{array}{c}-10\\-21\\-25\end{array}\right] = \left[\begin{array}{c}\frac{-8*-10 }{-81 } +\frac{16*-21 }{-81 } + \frac{-7*-25 }{-81 }\\\\\frac{-35*-10 }{-81 } +\frac{-11*-21 }{-81 }+ \frac{20*-25 }{-81 }\\\\\frac{-34*-10 }{-81 }+ \frac{-13*-21 }{-81 }+ \frac{31*-25 }{-81 }\end{array}\right] \\\\\

\left[\begin{array}{c}x\\y\\z\end{array}\right] = \left[\begin{array}{c}\frac{-81}{-81} \\\\\frac{81}{-81} \\\\\frac{-162}{-81} \end{array}\right] =  \left[\begin{array}{c}1\\-1\\2\end{array}\right]

Therefore, the correct option is (1,-1,2)

5 0
3 years ago
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