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irina [24]
3 years ago
13

Shawna packs blocks at the ABC blocks factory. She packs thousands in crates and tens in stacks. How can she pack an order for 1

,250 blocks using just crates and stacks?
Mathematics
1 answer:
Alex787 [66]3 years ago
3 0
She will pack 1 crate that holds 1,000 and 25 stacks that hold 10.
1,250-1,000=250
250÷10=25
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I hope that answers your question!

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Graph the line with slope 3 and y-intercept -8.
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There you go hope this helps

3 0
3 years ago
PLEASE ANSWER ASAP!!!! (and actually answer the question, no begging for "brainliest")
Zepler [3.9K]

Answer:

A: P = 41100 - 590t

B: 34610

Step-by-step explanation:

equation = 41100-(41100-36380)/(2011-2003)t

plug it in

41100 - 590(2014-2003)=34610

4 0
2 years ago
A student pushes a 51.5 kilogram bookshelf across a smooth floor with a net force of 67 N.
iren [92.7K]

The acceleration of the bookshelf is equal to 1.30 m/s^2

<u>Given the following data:</u>

  • Mass of bookshelf = 51.5 kilogram
  • Net force = 67 Newton

To determine the acceleration of the bookshelf, we would apply Newton's Second Law of Motion:

Newton's Second Law of Motion states that the acceleration of an object is directly proportional to the net force acting on the object while being inversely proportional to its mass.

Mathematically, Newton's Second Law of Motion is given by this formula;

Acceleration = \frac{Net\;force}{Mass}

Substituting the given parameters into the formula, we have;

Acceleration = \frac{67}{51.5}

Acceleration = 1.30 m/s^2

Read more on net force here: brainly.com/question/1121817

7 0
3 years ago
A poster is to have a total area of 125 cm2. There is a margin round the edges of 6 cm at the top and 4 cm at the sides and bott
jeka57 [31]

Answer:

The correct answer is 15 cm.

Step-by-step explanation:

Let the width of the required poster be a cm.

We need to have a 6 cm margin at the top and a 4 cm margin at the bottom. Thus total margin combining top and bottom is 10 cm.

Similarly total margin combining both the sides is (4+4=) 8 cm.

So the required printing area of the poster is given by {( a-10 ) × ( a - 8) } cm^{2}

This area is equal to 125 cm^{2} as per as the given problem.

∴ (a - 10) × (a - 8) = 125

⇒ a^{2} - 18 a +80 -125 =0

⇒ a^{2} - 18 a -45 = 0

⇒ (a-15) (a-3) = 0

By law of trichotomy the possible values of a are 15 and 3.

But a=3 is absurd as a > 4.

Thus the required answer is 15 cm.

7 0
3 years ago
Read 2 more answers
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