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irina [24]
3 years ago
13

Shawna packs blocks at the ABC blocks factory. She packs thousands in crates and tens in stacks. How can she pack an order for 1

,250 blocks using just crates and stacks?
Mathematics
1 answer:
Alex787 [66]3 years ago
3 0
She will pack 1 crate that holds 1,000 and 25 stacks that hold 10.
1,250-1,000=250
250÷10=25
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the area of a triangle is 124 square units. what would it's new area be if its base was half as long and its height was three ti
Montano1993 [528]
To solve this problem you must apply the proccedure shown below:

 1. You have that the formula for calculate the area of a triangle is:

 A=bh/2

 Where A is the area of the triangle, b is the base of the triangle and h is the height of the triangle.

 bh/2=124
 bh=124x2
 bh=248

 2. The problem asks for the new area of the triangle <span>if its base was half as long and its height was three times as long. Then, you have:

 Base=b/2
 Height=3h

 3. Therefore, when you substitute this into the formula for calculate the area of a triangle, you obtain:

 A'=bh/2

 (A' is the new area)

 A'=(b/2)(3)/2
 A'=3bh/4

 4. When you substitute bh=248 into </span>A'=3bh/4, you obtain:
<span>
 A'=186 units</span>²
<span>
 The answer is: </span>186 units²
3 0
3 years ago
How many solutions in the equation below 145=10x-8x
iren2701 [21]

Answer:

One

Step-by-step explanation:

145=2x

72.5=x that's one solution.

4 0
3 years ago
PLEASE HELP ASAP! WILL GIVE BRAINLEIST!<br> Find the area of the shaded region. Use pi = 3.14
Semmy [17]

Answer:

Step-by-step explanation:

Square

The side length of the square = 8 cm

The area of the square = s^2

The area of the square = 8^2 = 64

Circle

r = d/2

r = 8/2

r = 4

Area of the circle = pi r^2

Area of the circle = 3.14 * 16

Area of the circle = 50.24

Shaded Area

Area of the Shaded area = area Square - Area Circle

                                          = 64 - 40.24

                                          = 23.76

4 0
3 years ago
Find the slope between (0,3) and (6,2)
MArishka [77]
If u do the formula m=y^2-y^1/x^2-x^1 then u have 3-2/6-0 and that simplifies to 1/6 and that is your answer

answer: 1/6
8 0
3 years ago
Read 2 more answers
Use the diagram to determine which statement is true
hichkok12 [17]
A. Area of ABCD - Area of DGA = Area of DEFG
s^2 - 1/2bh = s^2
(5)^2 - 1/2(4)(3) = (3)^2
25 - 1/2(12) = 9
25 - 24 = 9
1 not equal to 9

B. Area of ABCD - Area of GHIA = Area of DGA
s^2 - s^2 = 1/2bh
(5)^2 - (4)^2 = 1/2(4)(3)
25 - 16 = 1/2(12)
9 not equal to 6

C. Area of ABCD + Area of DGA = Area of GHIA
s^2 + 1/2bh = s^2
(5)^2 + 1/2(4)(3) = (4)^2
25 + 1/2(12) = 16
25 + 6 = 16
31 not equal to 16

D. Area of DEFG + Area of GHIA = Area of ABCD
s^2 + s^2 = s^2
(3)^2 + (4)^2 = (5)^2
9 + 16 = 25
25 = 25

The answer is D.
5 0
3 years ago
Read 2 more answers
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