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Vikentia [17]
3 years ago
6

Two athletic directors purchased tennis balls and baseballs at the same store. The first athletic director bought 5 tennis balls

and 3 baseballs for a total of $23.75. The second athletic director bought 2 tennis balls and 7 baseballs for a total of $31.25.
What is the price of a baseball?
Mathematics
1 answer:
BartSMP [9]3 years ago
3 0

This question can be solved using 2 equations since there are 2 unknowns. First, let x = price of the tennis ball and y = price of the baseball. The resulting equations are: (1) 5x +3y = 23.75 and (2) 2x + 7y = 31.25. Solving the 2 equations simultaneously, you get, x = 2.5 and y = 3.75. The price of the baseball is then $3.75.

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Ruby ate 1/5 of a pie . If there was 10 slices of pie , how many did she eat . <br> SHOW YOUR WORK
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Ruby eats two slices of pie

Fraction generally represents a part of the whole. The number present in the upper side is called as numerator and the number present below is called as denominator. Fraction can also be represented as a decimal or percentage when required.

Fraction of pie Ruby ate = 1/5

Number of slices present in the pie = 10

numerical value of a fraction = fraction x total number

So, total number of slices of pie that Ruby ate = 10 x 1/5 = 2

Therefore, Ruby eats two slices of pie.

Ruby ate 1/5 of a pie and if there was 10 slices of pie, it implies Ruby eats two slices of pie.

To learn more about fraction refer here

brainly.com/question/11562149

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A manufacturer of potato chips would like to know whether its bag filling machine works correctly at the 420 gram setting. It is
anastassius [24]

Answer:

t=\frac{424-420}{\frac{26}{\sqrt{61}}}=1.202    

p_v =2*P(t_{(60)}>1.202)=0.234  

If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the true mean is NOT different from  420. So the specification is satisfied.

Step-by-step explanation:

Data given and notation  

\bar X=424 represent the sample mean

s=26 represent the sample standard deviation

n=61 sample size  

\mu_o =420 represent the value that we want to test

\alpha=0.01 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is different from 420 or not, the system of hypothesis would be:  

Null hypothesis:\mu = 420  

Alternative hypothesis:\mu \neq 420  

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:  

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic

We can replace in formula (1) the info given like this:  

t=\frac{424-420}{\frac{26}{\sqrt{61}}}=1.202    

P-value

The first step is calculate the degrees of freedom, on this case:  

df=n-1=61-1=60  

Since is a two sided test the p value would be:  

p_v =2*P(t_{(60)}>1.202)=0.234  

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If we compare the p value and the significance level given \alpha=0.01 we see that p_v>\alpha so we can conclude that we have enough evidence to fail reject the null hypothesis, so we can conclude that the true mean is NOT different from  420. So the specification is satisfied.

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