Say you have 3 cakes. How many cakes would you have eaten if you ate 1/3 of the three cakes? One, you have eaten one cake, out of the three you have.
How many cakes do you have left if you eat 2/3 of the three cakes? Two, you have eaten 2 cakes, and have 1 cake left.
It is a similar approach here, except the confusing part is working "forward", when you really have to work "backward". If you have driven 30 miles, and you have driven 2 parts out of the trip when there is 3 parts of the trip, how many miles have you driven? Hint: Dividing 30 by 2 gives you what fraction of the distance to Jeff's grandmother?
19/42=9 The input is a contradiction it has no solutions.
Answer:
8/3
Step-by-step explanation:
i put equations as this:
x+40 = y
where x is galllons of pure mixture and y is the gallons of the new mixture
the other equation i id was:
x+0.2(40) = 0.25y
x+8 = 0.25y
y = 4x+32
solve using substitution
(x+40) = 4x+32
x = 4x-8
-3x = -8
x = 8/3
Answer:
The nth term of the given sequence

Step-by-step explanation:
<u><em>Explanation:-</em></u>
Given sequence -5,-4,-1,4,11,20,31
a₀ = -5
a₁ = a₀ +1 = -5 +1 = -4
a₂ = a₁ + 3 = -4+3 = -1
a₃ = a₂ + 5 = -1 +5 = 4
a₄ = a₃ + 7 = 4 + 7 =11
a₅ = a₄ + 9 = 11+9 = 20
a₆ = a₅ + 11 = 20+11 = 31
a₇ = a₆ + 13 = 31 +13 =44
and so on
The nth term of the given sequence
