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alina1380 [7]
4 years ago
13

A rocket is launched at 85 feet per second from a launch pad that is 28 feet above the ground. Which equation can be used to det

ermine the height of the rocket at a given time after the launch?
Mathematics
2 answers:
alex41 [277]4 years ago
8 0

Answer:

the answer for this question is h(t)=-16t^2+85t+28

Step-by-step explanation:

i just took a test and this was one of the question and it told me this is the right   answer

Anestetic [448]4 years ago
7 0
Assuming the rocket flies in a straight line forever (as implied by your question),

y=85x+28

where

x = seconds after launch
y = feet above the ground
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77julia77 [94]

Answer:

Step-by-step explanation:

(A) Definition of Supplementary angles

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3 years ago
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Determine whether each of these sets is nite, countably in nite, or uncount- able. For those that are countably in nite, exhibit
ira [324]

Answer:

Integers that are divisible by 7 are countably infinite

The set are {7, 14, 21, 28, 35, 42, 49,......

Integers that are divisible by 10 are countably infinite

The set are {10, 20, 30, 40, 50, 60, 70,........

Also for the negative integers divisible by 7 or 10{.......,-49, -42, -35, -28, -21, -14, -7} or {........,-70, -60, -50, -40, -30, -20, -10} are countably infinite

Step-by-step explanation:

See the set of integers divisible by 7 or 10,

{7, 14, 21, 28, 35, 42, 49,........} Or

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So also, it is applicable in negative integers divisible by 7 or 10.

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A set is uncountable if it contains so many elements that they cannot be put in one-to-one correspondence with the set of natural numbers(Positive Integers). In other words, there is no way that one can count off all elements in the set in such a way that, even though the counting will take forever, you will get to any particular element in a finite amount of time.

WHILE

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3 0
3 years ago
If x=7cm what is the surface area of the geometric shape formed by this net
Mekhanik [1.2K]
There are four rectangles and 2 squares.

Let’s start with the four rectangles.
4 [ 2x(x)]
4 [ (2*7)(7)] = 392 cm^2
______________

Next, let’s find the SA for the two squares.
2 [(2x)^2]
** I need to be clear that both the 2 and the x in the parentheses are squared because the square, of course, is a “perfect square”. This was probably obvious and needless to say, haha oh well.
Next step: plug in values
2 [ [2(7)]^2 ] = 392 cm^2

TOTAL: 392+392 = 784 cm^2

Wow I should have realized the the 4 rectangles are the area as the two squares.

Good luck to you!
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Answer:

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