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Reika [66]
3 years ago
11

a) The average height of sunflowers in a field is 64 inches with a standard deviation of 3.5 inches. Describe a normal curve for

the distribution, including the values on the horizontal axis at one, two, and three standard deviations from the mean. b) If there are 3,000 plants in the field, approximately how many will be taller than 71 inches?
Mathematics
1 answer:
tresset_1 [31]3 years ago
8 0
The values on the horizontal axis are:
at 0 = 64
at one standard deviation (lower, upper) = (60.5 , 67.5)
at two standard deviation (lower, upper) = (57 , 71)
at three standard deviation (lower, upper) = (53.5 , 74,5)

B. P(x > 71) = 1 - P(x < 71) = 1 - P[z < (71 - 64)/3.5] = 1 - P(z < 2) = 1 - 0.97725 = 0.02275
Therefore the no of plants taller than 71 inches will be approximately 0.02275 * 3000 = 68

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<h3>The student with the accurate description</h3>

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Hello guys, plz help me with this question ASAP! Plz show the working, THANK YOU BROTHER
RoseWind [281]

Answer:

5.5 min

Step-by-step explanation:

At time t=0 you have 72 grams

at time t = 22 min you have 4.5 grams.

Now

4.5/72 = (1/2)^(t/half-life)

and t=22, so

4.5/72 = (1/2)^(22/half-life)

taking log of both sides:

log(4.5/72)=(22/half-life)log(1/2)

solving for half-life gives half-life = 11/2 = 5.5min

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bagirrra123 [75]

Answer: C

Step-by-step explanation:

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ABC was dilated to create A'B'C. What is the scale factor of the dilation?
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Step-by-step explanation:

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The weight of extra-large egg has a Normal distribution with a mean of 3 oz and a standard deviation of 0.1 oz. In sampling dist
seropon [69]

Answer:

Probability = 0.4443

Step-by-step explanation:

The provided information is:

Consider X be the weight of extra-large egg that is normally distributed with mean \mu=3 \,oz and standard deviation \sigma = 0.1 \,oz

Also, sample size n = 12.

Thus, the probability that an egg in a carton of a dozen eggs weights more than 3.5 oz is:

\begin{aligned}P( X > 3.5) &= P(Z >\frac{3.5-3}{\frac{0.1}{\sqrt{12}}})\\&=P(Z>0.14)\\&=1-P(Z\leq0.14)\\&=1-0.557\\&=0.4443\end{aligned}

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3 years ago
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