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8_murik_8 [283]
3 years ago
12

I do not understand what to do for 2-4

Mathematics
1 answer:
Tasya [4]3 years ago
6 0
Well umm i don't really have the answer, but... you should be a bit more careful when you take pictures of your papers, your name is shown...
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The cost of C (in dollars) of making n watches is represented by C=15n+85. How many watches are made when the cost is $385?
hichkok12 [17]

well...

15 x 20 = 300

300+85 = 385


you can get 20 watches for $385


4 0
3 years ago
Help if u understand pleas and thanks
Gala2k [10]

Answer:

3f

Step-by-step explanation:

f+f+f=3f

since every f has the same value

example

2+2+2=3(2)

6=6

6 0
3 years ago
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How to find coordinates of a point using ratio
Marat540 [252]

m1=3, m2= 1

point A= (-5,4)

point B=(7,-2)

x=m1x2+m2x1/ m1+m2 , y=m1y2+m2y1 / m1+m2

x= 3×7 +1×-5/3+1 , y= 3×-2+1×4 / 3+1

x= 21-5/4, y= -6+4/4

x= 16/4, y= -2/4

x= 4, y= 0.5

5 0
3 years ago
Ben drove 230 kilometers in 3 hours, and pia drove 250 km in 3 hours. Without making any calculations, who drove faster? Explain
vovangra [49]
Pia drove faster because she went farther than Ben in 3 hours.
8 0
3 years ago
Read 2 more answers
Help me with this. I am really stuck.
Kryger [21]

By the Hypotenuse Leg theorem, the two triangles are congruent. That is, ΔBXA ≅ ΔBYA

From the question, we are to prove that ΔBXA ≅ ΔBYA

From the Hypotenuse Leg theorem which states that "two right triangles are congruent if the hypotenuse and one leg of one right triangle are congruent to the other right triangle's hypotenuse and leg side".

From the given information,

BX ⊥ XA.

ΔBXA is right triangle with hypotenuse AB

Also,

BY ⊥ YA.

ΔBYA is right triangle with hypotenuse AB

∴ The hypotenuses of the triangles are congruent

Also, from the given information,

XA is congruent to YA

XA and YA are the legs of the right triangles.

Hence, by the Hypotenuse Leg theorem, the two triangles are congruent. That is, ΔBXA ≅ ΔBYA

Learn more on Congruent triangles here: brainly.com/question/27983954

#SPJ1

7 0
1 year ago
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