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arlik [135]
3 years ago
11

Find the surface area and volume. Answer SA = ____, V= _______

Mathematics
1 answer:
Tomtit [17]3 years ago
8 0

Answer:

SA = 251.33 yd ^2

V = 301.59 yd ^3

Step-by-step explanation:

Right cylinder   2π  = 6.28318530718

Solve for surface area

A =2πrh+2πr2  = 24 x 2π + 2π x 16

A =150.796447372 + 100.530964915

A ≈251.33 yd^2

Right cylinder π = 3.14159265359

Solve for volume

V = πr2h = 16 x 6 = 96π

V = 3.14159265359 x 96

V = 301.592894745

V= 301.59 yd ^3

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Irina18 [472]

Answer:

the anser should be 12 because 8+4=12

Step-by-step explanation:

5 0
4 years ago
Please help ! ALGEBRA 1
aliina [53]

Answer:

Option B is the correct answer.

Step-by-step explanation:

0. \overline{79} +   \pi

Here 0.\overline{79} is a rational number and \pi is an irrational number whose sum gives irrational number.

8 0
3 years ago
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A 15-foot ladder is leaning against a house. the base of the ladder is 4 feet from the house. to the nearest tenth of a foot, ho
adell [148]
The correct question is
<span>A 15-foot ladder is leaning against a house. the base of the ladder is 4 feet from the house. to the nearest tenth of a foot. </span>How high up the house does the ladder reach?

see the picture attached to better understand the problem

applying the Pythagoras Theorem
15²=4²+h²-----> h²=15²-4²-----> h²=225-16----> h=√209
h=14.46 ft------> h=14.5 ft

the answer is
14.5 ft

3 0
3 years ago
Which number line represents the solution to the inequality 125x + 200 &gt; 1,200?
Elza [17]

Answer:

see below

Step-by-step explanation:

25x + 200 > 1,200

Subtract 200 from each side

25x + 200-200 > 1,200-200

25x> 1000

Divide by 25

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6 0
3 years ago
Suppose that a function​ f(x) is defined for all real values of x except at xequals=c. can anything be said about the existence
Margaret [11]

we are given that

f(x) is defined for all values of x except at x=c

Limit may or may not exist

case-1:

If there is hole at x=c , then limit exist

case-2:

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Examples:

case-1:

\lim_{x \to c} \frac{x^2-cx}{(x-c)}

We can simplify it

\lim_{x \to c} \frac{x(x-c)}{(x-c)}

=\lim_{x \to c} x

=c

so, we can see that limit exist and it's value defined

case-2:

\lim_{x \to c} \frac{1}{(x-c)}

Left limit is

\lim_{x \to c-} \frac{1}{(x-c)}

=-\infty

Right Limit is

\lim_{x \to c+} \frac{1}{(x-c)}

=+\infty

so, we can see that left limit is not equal to right limit

so, limit does not exist

4 0
3 years ago
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