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3 years ago

After a discount of 40%, the sale price of a ride pass at a fun park is $30. What is the original

Mathematics

2 answers:

ipn [44]3 years ago

8 0

30 divided by 0.40 = 75

The original price was $75

777dan777 [17]3 years ago

7 0

Answer:

30 divided by 0.40 = 75

The original price was $75

Step-by-step explanation:

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The given diagram shows the parts of a right triangle with an altitude to the hypotenuse. Using the two given measures, find th

almond37 [142]

I only could find part of the triangle sorry, but u1 is 2 radical 2

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3 years ago

Using the quadratic formula to solve x2 + 20 = 2x, what are the values of x?

jeka94

by Quadratic formula , $x^2 + 20 = 2x$ , values of x are $x = 1 \pm (1)i\sqrt{19}}$ . None of mentioned options are correct according to question!

<u>Step-by-step explanation:</u>

Here we have , expression x2 + 20 = 2x or , $x^2 + 20 = 2x$ .

We know that Quadratic formula is :

$x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$

$x^2 + 20 = 2x$

⇒ $x^2-2x+20=0$

$a=1\\b=-2\\c=20$

Putting this value in equation $x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$ :

⇒ $x = \frac{-b \pm \sqrt{b^{2}-4ac}}{2a}$

⇒ $x = \frac{-(-2) \pm \sqrt{(-2)^{2}-4(1)(20)}}{2(1)}$

⇒ $x = \frac{2 \pm \sqrt{4-80}}{2}$

⇒ $x = (\frac{2 \pm 2i\sqrt{19}}{2})$

⇒ $x = 1 \pm (1)i\sqrt{19}}$

Therefore , by Quadratic formula , $x^2 + 20 = 2x$ , values of x are $x = 1 \pm (1)i\sqrt{19}}$ . None of mentioned options are correct according to question!

7 0

3 years ago

Leena bought 14 yards of wire. How many inches of wire did she buy? (1 yard = 36 inches)

Anastasy [175]

Answer:

Step-by-step explanation:

1 yard=3 feet=36

14 yards x 36= 504

14 yards = 504 inches

mark as brainliest :)

7 0

3 years ago

Read 2 more answers

F(x) = x ^ 2 . What is g(x) ?

Bond [772]

Given:

The function is:

$f(x)=x^2$

The graphs of functions $f(x)$ and $g(x)$ .

To find:

The function $g(x)$ .

Solution:

We have,

$f(x)=x^2$

The function $f(x)$ is vertically compresses to get the graph of the function $g(x)$ . So, the function $g(x)$ is:

$g(x)=kf(x)$

$g(x)=kx^2$ ...(i)

From the given graph it is clear that the graph of the function $g(x)$ passes through the point (3,3). So, putting $x=3$ and $g(x)=3$ in the above function, we get