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Vilka [71]
3 years ago
11

Two physics students are doing a side competition during a game of bowling, seeing who can toss a ball with the larger momentum.

The first bowler throws a 4.5 kg ball at 8.6 m/s. Part A A second bowler throws a 6.4 kg ball. What speed must she beat to win the competition?
Mathematics
1 answer:
dem82 [27]3 years ago
6 0

Answer:

she should beat a speed of  v₂ = 6.04 m/s in order to win the competition

Step-by-step explanation:

Since the momentum p is defined as

p = m*v

where

m= mass of the ball

v= velocity of the ball

denoting 1 and 2 as the first and second bowler , then to reach the momentum of the first bowler

p₂=p₁

therefore

m₁*v₁ = m₂*v₂

v₂ = v₁ * (m₁/m₂)

replacing values

v₂ = v₁ * (m₁/m₂) =8.6 m/s * (4.5 kg/6.4 kg ball) = 6.04 m/s

then since the momentum p = m*v increases with increasing v (at constant m)  , she should beat a speed of  v₂ = 6.04 m/s in order to win the competition

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In order to solve this summation formula, you need to first understand what it means. The summation symbol is tell you to add the terms in a sequence. Below the summation sign, there is a variable and number; the variable n is the index of summation and the number 1 is the lower limit of summation or the first value of the sequence. The number 25 above the summation sign is the upper limit (so there would be 25 terms, with the first being 1). The polynomial to the right of the summation symbol represents the explicit function for each term. For example, using this, the first term would be (3(1) - 2) and the second (3(2) - 2) and so on. This means the value of that equation is:

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= 975 - 50

= 925

3 0
2 years ago
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