1. Parabola's equation is y = a(x + b)^2 + c, where (b, c) is the vertex.
2. We have y = a(x - 3)^2 + 1
3. Take everything to the left side:
-a(x - 3)^2 + y - 1 = 0
That's the standard equation. Hope this helps! :)
So consecutive intergers are 1 away from each other so
the numbers are
x,x+1,x+2
if the product (multily) of 2 smaeller is 5 less than 5 times largest so
(x times (x+1)) is 5 less than 5 times (x+2)
(x times (x+1))=-5+5(x+2)
pemdas
distribute using distributiver property
a(b+c)=ab+ac so
x times (x+1)=x^2+x
5(x+2)=5x+10
we have
x^2+x=-5+5x+10
add like terms
x^2+x=5x+5
subtract (5x+5) from both sides
x^2-4x-5=0
factor by find what 2 numbers add to -4 and multply to get -5
numbers are 1 and -5
so we do
(x+1)(x-5)=0
sete each to zero
x+1=0
x-5=0
x+1=0
sbtract 1
x=-1
we want positie so thisis wrong answer
x-5=0
add 5
x=5
subsitute
x,x+1,x+2
5,5+1,5+2
5,6,7
smalles is 5
-9x-5y=12
C) (2, -6) -18+30=12
You have to fraw sticks as the 10's for example #2 prtend thise are the sticks.(I)
IIII 4 tens in 42 the circles as ones O O SO,IIII00
Sin <P = opp/hyp = 12/13
m <P = 67.38 degrees