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natka813 [3]
3 years ago
13

Point A is the midpoint of segment PT

Mathematics
1 answer:
IceJOKER [234]3 years ago
8 0
Yes you are correct
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Find the value of 4x if x/2=3
Doss [256]

Answer:

24

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

x/2 = 3

x = 3×2

x = 6

Therefore

4x = 4 × 6

4x = 24

4 0
3 years ago
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Simplify. (-1/2√2)(-6√18) 18 -18 -36
olga_2 [115]

Hey!

Your answer is solved below/above idk wherever just see in the picture.

8 0
3 years ago
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Jill arranges quarters in stacks of increasing powers of 2, starting with the zeroth power (20). If she ends up with six stacks,
Ratling [72]
Stack 1 : 2^0 = 1 quarter.
Stack 2 : 2^1 = 2 quarters.
Stack 3: 2^2 = 4 quarters.
Stack 4: 2^3 = 8 quarters.
Stack 5 : 2^4 = 16 quarters.
Stack 6: 2^5 = 32 quarters.
1 + 2 + 4 + 8 + 16 + 32 = 63
Answer: She used 63 quarters. 
8 0
3 years ago
A rectangular box is to have a square base and a volume of 20 ft3. If the material for the base costs $0.35 per square foot, the
denpristay [2]

Answer:

Length = 2 ft

Width = 2 ft

Height = 5 ft

Step-by-step explanation:

Let the square base of the box has one side = x ft

Therefore, area of the base = x² ft²

Cost of the material to prepare the base = $0.35 per square feet

Cost to prepare the base = $0.35x²

Let the height of the box = y ft

Then the volume of the box = x²y ft³ = 20

y=\frac{20}{x^{3} } -----(1)

Cost of the material for the sides = $0.10 per square feet

Area of the sides = 4xy

Cost to prepare the sides of the box = $0.10 × 4xy

                                                             = $0.40xy

Cost of the material to prepare the top = $0.15 per square feet

Cost to prepare the top = $0.15x²

Total cost of the box = 0.35x² + 0.40xy + 0.15x²

From equation (1),

Total cost C=0.35x^{2}+(0.40x)\times \frac{20}{x^{2} }+0.15x^{2}

C=0.35x^{2}+\frac{8}{x}+0.15x^{2}

C=0.5x^{2}+\frac{8}{x}

Now we take the derivative of C with respect to x and equate it to zero,

C'=0.5(2x)-\frac{8}{x^{2}} = 0

x-\frac{8}{x^{2}}=0

x=\frac{8}{x^{2} }

x^{3}=8

x = 2 ft.

From equation (1),

(2)^{2}y=20

4y = 20

y = 5 ft

Therefore, Length and width of the box should be 2 ft and height of the box should be 5 ft for the minimum cost to construct the rectangular box.

8 0
3 years ago
Julia and Kajal make deliveries on their bicycles. For each delivery, they need some time to get ready, and then they each ride
UNO [17]

For Julia’s case, we determine first he time it takes her to ride or cover every kilometre knowing that 10 minutes of the given 40 minutes is used for the preparation.

 

<span>    r (Julia) = (40 – 10 min) / 5 km = 6 minutes per kilometre</span>

 

<span>A.    </span>The time it takes Julia to get ready is only 10 minutes while from the given equation, the time it takes Kajal to get ready is 15 minutes. Hence, the answer is Kajal.

<span>B.    </span><span>From the calculation above, it takes Julia 6 minutes to cover a kilometre. From the equation, it is also given that Kajal takes 6 minutes to cover every kilometre. Hence, the answer is Neither as they travel at the same rate. </span>

5 0
3 years ago
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