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snow_lady [41]
3 years ago
14

Given: x + y = 15. Which of the following are ordered pairs of this equation?

Mathematics
2 answers:
Dmitry_Shevchenko [17]3 years ago
6 0
(0,5)(1,4)(2,3) I got those
OverLord2011 [107]3 years ago
5 0
The answer is most likely:

(0-5) (1-4) (2-3)

A Branliest or just a thanks would be terrific!

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Write 2x - x2 = 1 in standard form.<br> An equation in standard form is
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When p = 12, t = 2, and s = One-sixth, r = 18. If r varies directly with p and inversely with the product of s and t, what is th
bagirrra123 [75]

Answer:

k = \frac{1}{2}

Step-by-step explanation:

Given

p = 12

t = 2

s = \frac{1}{6}

r = 18

r\ \alpha\ p\ * \frac{1}{s * t}

Required

Find the constant of variation

From the question, the variation is as follows

r\ \alpha\ p\ * \frac{1}{s * t}

r\ \alpha\ \frac{p * 1}{s * t}

r\ \alpha\ \frac{p}{s * t}

Convert variation to equation

r\ = k\frac{p}{s * t}

Where k represents the constant of variation

Make k the subject of formula;

Multiply both sides by s * t

r * s * t = k\frac{p}{s * t} * s * t

r * s * t = kp

Divide both sides by p

\frac{r * s * t}{p} = \frac{kp}{p}

\frac{r * s * t}{p} = k

k = \frac{r * s * t}{p}

Substitute the values of p, r, s and t in the above equation

k = \frac{18 * \frac{1}{6} * 2}{12}

k = \frac{6}{12}

Divide numerator and denominator by 6

k = \frac{1}{2}

Hence, the constant of variation is; k = \frac{1}{2}

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3 years ago
...........................answer
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ANSWER:D.(30)..........
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