All categories

3 years ago

Which of these statements about the function is true?

Mathematics

1 answer:

zepelin [54]3 years ago

6 0

Answer: It is not continuous at x=3

You might be interested in

5(t+3)=-3.5 solve for t

mestny [16]

Answer: t=−3.7

If I Helped, Please Mark Me As Brainliest, Have A Great Day :D

8 0

3 years ago

Read 2 more answers

Please help me with this

Tcecarenko [31]

Answer:

808+808=1616 340+340=680 then 1616-680=976

Step-by-step explanation:

you need to add 808 plus 808 which is 1616 then add 340 plus 340 which is 680, then subtract 1616-680 which is 976.

8 0

3 years ago

What is the second factor when 0.200 is written scientific notation

Phoenix [80]

Answer:

2*10^-1

Step-by-step explanation:

U shud know y

5 0

3 years ago

What is the slope of the line that passes through the points (7, -4) and (7, 0)? Write your answer in the simplest form.

olga55 [171]

Answer:

The slop is undefined

i.e. $m=\infty$

Step-by-step explanation:

Considering the slope formula

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

As the points are (7, -4) and (7, 0)

Here:

(x₁, y₁) = (7, -4)

(x₂, y₂) = (7, 0)

$\mathrm{When\:}y_1\ne \:y_2\mathrm{\:and\:}\:x_1=x_2\mathrm{\:the\:slope\:is\:}\infty$

$\mathrm{Slope}=\frac{y_2-y_1}{x_2-x_1}$

$=\frac{\left(0-\left(-4\right)\right)}{\left(7-7\right)}$

$=\frac{0-\left(-4\right)}{0}$

$=\infty$

Therefore, the slop is undefined i.e. $m=\infty$

5 0

3 years ago

Consider two independent tosses of a fair coin. Let A be the event that the first toss results in heads, let B be the event that

aliina [53]

Answer with Step-by-step explanation:

We are given that two independent tosses of a fair coin.

Sample space={HH,HT,TH,TT}

We have to find that A, B and C are pairwise independent.

According to question

A={HH,HT}

B={HH,TH}

C={TT,HH}

$A\cap B=$ {HH}

$B\cap C$ ={HH}

$A\cap C$ ={HH}

P(E)= $\frac{number\;of\;favorable\;cases}{total\;number\;of\;cases}$

Using the formula

Then, we get

Total number of cases=4

Number of favorable cases to event A=2

$P(A)=\frac{2}{4}=\frac{1}{2}$

Number of favorable cases to event B=2

Number of favorable cases to event C=2

$P(B)=\frac{2}{4}=\frac{1}{2}$

$P(C)=\frac{2}{4}=\frac{1}{2}$

If the two events A and B are independent then

$P(A)\cdot P(B)=P(A\cap B)$

$P(A\cap)=\frac{1}{4}$

$P(B\cap C)=\frac{1}{4}$

$P(A\cap C)=\frac{1}{4}$

$P(A)\cdot P(B)=\frac{1}{2}\cdot \frac{1}{2}=\frac{1}{4}$

$P(B)\cdot P(C)=\frac{1}{4}$

$P(A)\cdot P(C)=\frac{1}{4}$

$P(A)\cdot P(B)=P(A\cap B)$

Therefore, A and B are independent

$P(B)\cdot P(C)=P(B\cap C)$

Therefore, B and C are independent

$P(A\cap C)=P(A)\cdot P(C)$

Therefore, A and C are independent.

Hence, A, B and C are pairwise independent.

6 0

3 years ago