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3 years ago

What is the maximum for g(x)

Mathematics

2 answers:

saul85 [17]3 years ago

4 0

Answer:

the maximum is the greatest point on a graph. When a parabola opens downward, the maximum is the vertex.

in this graph the maximum is (0,1)

IRISSAK [1]3 years ago

3 0

Answer:

The local maximum value is 1.

Step-by-step explanation:

The maximum is at the peak of the loop at the point (0, 1.)

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The left and right page numbers of an open book are consecutive integers whose sum is 53. Find these page numbers.

Mice21 [21]

26 left 27 right. If you add them together, you get a sum of 53

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3 years ago

Simplify 7(A - 6). 7A - 42 7A - 6 A - 6 FIRST ONE GETS A BRAIN LIST?!

Cerrena [4.2K]

Answer:

7A - 42

Step-by-step explanation:

$7(A - 6) \\ = 7A - 7 \times 6 \\ = 7A - 42$

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3 years ago

Read 2 more answers

At your full-service. 500 room hotel, typically, 1/4 of the guests will request

monitta

B. 875
1/4 of 500 is 125. So 125 is how much they pay for day approx. 125 times the seven days will be 875.

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3 years ago

If the supplies cost $1.50 per jar and he has a markup of 90% what price dose he sell it for ?

prisoha [69]

Answer:

2.85

Step-by-step explanation:

100%->1.50

1%->0.015

190%->2.85

7 0

3 years ago

Almost all medical schools in the United States require students to take the Medical College Admission Test (MCAT). To estimate

yKpoI14uk [10]

Answer:

a) 0.5588

b) 0.9984

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 24

Standard Deviation, σ = 6.4

We are given that the distribution of score is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

a) P(score between 20 and 30)

$P(20 \leq x \leq 30) = P(\displaystyle\frac{20 - 24}{6.4} \leq z \leq \displaystyle\frac{30-24}{6.4}) = P(-0.62 \leq z \leq 0.94)\\\\= P(z \leq 0.94) - P(z < -0.62)\\= 0.8264 - 0.2676 = 0.5588 = 55.88\%$

$P(20 \leq x \leq 30) = 55.88\%$

b) Sampling distribution

Sample size, n = 22

The sample will follow a normal distribution with mean 24 and standard deviation,

$s = \dfrac{\sigma}{\sqrt{n}} = \dfrac{6.4}{\sqrt{22}} =1.36$

c) P(mean score of sample is between 20 and 30)

$P(20 \leq x \leq 30) = P(\displaystyle\frac{20 - 24}{1.36} \leq z \leq \displaystyle\frac{30-24}{1.36}) = P(-2.94 \leq z \leq 4.41)\\\\= P(z \leq 4.41) - P(z < -2.94)\\= 1 - 0.0016 = 0.9984 = 99.84\%$

$P(20 \leq x \leq 30) =99.84\%$

5 0

4 years ago