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Ronch [10]
4 years ago
14

A couple has three children. Assuming each child has an equal chance of being a boy or a girl, what is the probability that they

have at least one girl
Mathematics
1 answer:
krok68 [10]4 years ago
4 0

Answer: 7/8

Step-by-step explanation:

Let the boy is letter B and the girl is letter G.

So the possible outcomes are as follows below

BBB, BBG, BGB, GBB, BGG, GBG, GGB, GGG

SO the number of possible outcomes is 8

The number of outcomes where is at least 1 girl ( triples where is 1 girl, 2 girls or all 3 children are the girls) is 7

So the probability, that family with 3 kids has at least 1 girl is

P(number of girls >=1)=  7/8  

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Ratio of width to length:    W/L = 3/5
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Perimeter = 2*(L+W) = 80

2*(L+W) = 80
(L+W) = 80/2.  Divide both sides by 2.
L+W= 40......(b)


5W = 3L

L + W = 40    Multiply both sides by 5.
5*(L+W) = 5*40
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L = 200/8
L = 25.

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4 years ago
Simplify 5a+6a2+7a-4a2-9a
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