2.67 is greater than 2 2/3
Answer: C
Step-by-step explanation:
Hello!
If you do not know 1 question;
100-20=80
If you do not know 2 question;
20+20=40 100-40=60
If you do not know 3 question;
20+20+20=60 100-60=40
If you do not know 4 question;
20+20+20+20=80 100-80=20
If you do not know 5 question;
20+20+20+20+20=100 100-100=0
<span>
</span>
The 90% confidence interval is given by mean - 1.645(s.d. / sqrt(n)) < μ < mean + 1.645(s.d. / sqrt(n))
mean - 1.645(s.d. / sqrt(n)) + mean + 1.645(s.d. / sqrt(n)) = 2<span>μ = 5.22 + 5.98 = 11.2
</span><span>μ = 11.2 / 2 = 5.6
Thus, </span><span>mean - 1.645(s.d. / sqrt(n)) = 5.6</span><span> - 1.645(s.d. / sqrt(n)) = 5.22
5.6 - 5.22 = </span><span>1.645(s.d. / sqrt(n)) = 0.38
</span><span><span>s.d. / sqrt(n) = 0.38 / 1.645 = 0.231
</span>The 95% confidence interval is given by </span>mean - 1.96(s.d. / sqrt(n)) < μ < mean + 1.96(s.d. / sqrt(n)) = 5.6 - 1.96(0.231) < <span>μ < 5.6 + 1.96(0.231) = 5.6 - 0.4528 < </span><span>μ < 5.6 + 0.4528 = 5.15 < </span><span>μ < 6.05
The 95% confidence interval provides more information because it has a larger interval.</span>
Answer:
Step-by-step explanation:
if you need help let me know