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3 years ago

How do tou do it I xo not under stand

Mathematics

1 answer:

iren [92.7K]3 years ago

4 0

For x > 2, you would circle the 2, but you would not shade it in because it is greater than/ less than, not greater than or equal to/less than or equal to. From there on, you would move it to the right, because here x is greater than 2, and the numbers to the right of 2 are greater than two.

For x < 2, you would again circle the 2, but don't shade it in. And then you would make a line heading towards the left, because the numbers to the left of 2 are smaller than 2, and here, x is smaller than 2, since 2 is greater.

A value that is not the solution to either inequality is 2. 2 is not greater than 2, and 2 is not less than 2.

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3 years ago

Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. Illustra

Rainbow [258]

Answer:

$x = t$

$y = 1 - t$

$z = 2t$

Step-by-step explanation:

Given

$x=t$

$y=e^{-t}$

$z=2t-t^2$

(0, 1, 0)

The vector equation is given as:

$r(t) = (x,y,z)$

Substitute values for x, y and z

$r(t) = (t,\ e^{-t},\ 2t - t^2)$

Differentiate:

$r'(t) = (1,\ -e^{-t},\ 2 - 2t)$

The parametric value that corresponds to (0, 1, 0) is:

$t = 0$

Substitute 0 for t in r'(t)

$r'(t) = (1,\ -e^{-t},\ 2 - 2t)$

$r'(0) = (1,\ -e^{-0},\ 2 - 2*0)$

$r'(0) = (1,\ -1,\ 2 - 0)$

$r'(0) = (1,\ -1,\ 2)$

The tangent line passes through (0, 1, 0) and the tangent line is parallel to r'(0)

It should be noted that:

The equation of a line through position vector a and parallel to vector v is given as:

$r(t) = a + tv$

Such that:

$a = (0,1,0)$ and $v = r'(0) = (1,-1,2)$

The equation becomes:

$r(t) = (0,1,0) + t(1,-1,2)$

$r(t) = (0,1,0) + (t,-t,2t)$

$r(t) = (0+t,1-t,0+2t)$

$r(t) = (t,1-t,2t)$

By comparison:

$r(t) = (x,y,z)$ and $r(t) = (t,1-t,2t)$

The parametric equations for the tangent line are:

$x = t$

$y = 1 - t$

$z = 2t$

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3 years ago

Which of the following graphs the equation. <br> Y=1/3x -2

olga_2 [115]

Answer:

I don't know your answer options, but this is what the graph would look like:

**please mark brainliest!!

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3 years ago

WILL GIVE BRAINY!!

Illusion [34]

Answer:

Step-by-step explanation:

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8 0

3 years ago

Read 2 more answers

Percent rate of change for the function y=(.94)^x

NeX [460]

$\bf \qquad \textit{Amount for Exponential Decay}\\\\
y=I(1 - r)^x\qquad 
\begin{cases}
y=\textit{accumulated amount}\\
I=\textit{initial amount}\\
r=rate\to r\%\to \frac{r}{100}\\
x=\textit{elapsed time}\\
\end{cases}
\\\\\\
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\\\\\\
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4 years ago