<h3>
Answer:</h3>
<u>Perimeter of rectangular garden = 2(l + b)</u>
- 2(y + 2 + 4y - 1)
- 2y + 4 + 8y - 2
- 10y + 2.
<u>Hence, perimeter of given garden is 10y + 2</u>.
5 would have to be the constant, because in algebraic terms, a constant is a term that contains only numbers and no variables, which would knock 2x right out of the question. Hope I helped.
Answer:
<u>Percent air is calculated as:</u>
- Percent air = Current amount/Total amount *100
<u>Solve for total amount of air:</u>
- Total amount = Current amount / Percent air * 100
Substitute the values in hand to get the answer
Answers:
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Question 1) The correct answer is: [C]: " 5 " .
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Question 2) The correct answer is: [C]: "-24 " .
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Explanation:
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Question #1)
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The "denominator" must not equal "zero" ;
since one cannot "divide by zero" ;
As such, the value of the "denominator"; which is: "(9x − 45)" ;
cannot equal "zero".
So, what is the value of "x" when: "9x − 45 = 0" ? ;
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Method 1)
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" 9x − 45 = 0 " ; Solve for "x" ;
Add "45" to each side of the equation;
9x − 45 + 45 = 0 + 45 ;
to get:
9x = 45 ;
Divide each side of the equation by "9" ;
to isolate "x" on one side of the equation; & to solve for "x" ;
9x / 9 = 45 / 9 ;
x = 5 ; which is: Answer choice: [C]: "5" .
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Method 2)
" 9x − 45 = 0 " ; Solve for "x" ;
→ Factor out a "9" in: " 9x − 45" ; and rewrite:
→ " 9(x − 5) = 0 " ;
Divide EACH SIDE of the equation by "9" ;
→ " { [9(x − 5)] / 9 } = { 0 / 9 } ;
→ x − 5 = 0 ;
Add "5" to EACH SIDE of the equation;
to isolate "x" on one side of the equation; & to solve for "x" ;
→ x − 5 + 5 = 0 + 5 ;
→ x = 5 ; which is: Answer choice: [C]: " 5 " .
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Question #2)
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Again, note that the "denominator" must not equal "zero" ; since one cannot "divide by zero" ;
As such, the value of the "denominator"; which is: "2x + 48" ; cannot equal "zero".
So, what is the value of "x" when: "2x + 48 = 0" ? ;
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Method 1)
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" 2x + 48 = 0 " ; Solve for "x" ;
Subtract "48" from each side of the equation;
2x + 48 − 48 = 0 − 48 ;
to get:
2x = -48 ;
Divide each side of the equation by "2" ;
to isolate "x" on one side of the equation; & to solve for "x" ;
2x / 2 = -48 / 2 ;
x = -24 ; which is: Answer choice: [C]: "-24" .
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Method 2)
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" 2x + 48 = 0 " ; Solve for "x" ;
→ Factor out a "2" in: " 2x + 48" ; and rewrite:
→ " 2(x + 24) = 0 " ;
Divide EACH SIDE of the equation by "2" ;
→ " { [2(x + 24)] / 2 } = { 0 / 2 } ;
→ x + 24 = 0 ;
Subtract "24" from EACH SIDE of the equation;
to isolate "x" on one side of the equation; & to solve for "x" ;
→ x + 24 − 24 = 0 − 24 ;
→ x = -24 ; which is: Answer choice: [C]: " -24 " .
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Method 3)
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" 2x + 48 = 0 " ; Solve for "x" ;
→ Divide the entire equation (both sides) by "2" ; to simplify :
{2x + 48} / 2 = 0/ 2 ;
to get:
x + 24 = 0 ;
Subtract "24" from EACH SIDE of the equation;
to isolate "x" on one side of the equation; & to solve for "x" ;
→ x + 24 − 24 = 0 − 24 ;
→ x = -24 ; which is: Answer choice: [C]: " -24 " .
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Gotta convert this to make it save some time.
1 over 18 = 1/18
1 over 3 = 1/3
If 1/18 of a lawn is wattered in 20 mins, (Simply coverting 1/3 hr to mins by doing 60/3) 20 * 18 = 360 Mins = 6 Hours
It takes 6 hours to water the entire lawn