Question

Find the discriminant of (x+5)^2 = 2( 5x-3)

Answer 1

Step-by-step explanation:

(x+5)^2 = 2( 5x-3)

x^2+25=10x-6

x^2-10x+25+6= 0

x^2-10x+31=0

a=1, b

Answer 2

Answer:

$\boxed{-124}$

Step-by-step explanation:

$(x+5)^2 = 2( 5x-3)\\x^2+10x+25=10x-6\\x^2+0x+31=0$

$ax^2 +bx +c=0$

Formula for the discriminant:

$D=b^2-4ac$

$b=0\\a=1\\c=31$

Plug in the values.

$D=0^2-4(1)(31)$

$D=-124$