To solve this problem you must apply the proccedure showb below:
1. You have the following equation:
<span> 2x^2+9y^2=18
2. Dividing the equation by 18, you have:
(x^2/9)+(y^2/2)=1
3. The center is:
[</span>(x-0)^2/9]3^2[(y-0)^2/√2]=1
<span>
(h,k)=(0,0)
The center is (0,0)
4. The vertices are:
a^2=9
a=3
Vertices: (-3,0) and (3,0)
5. The foci is:
c^2=a^2-b^2
c=</span>√7
<span>
The foci is: (-</span>√7,0) and (√7,0)
Here you go 2v + 3b - v(2)
Answer:
The answer is 4 1/8
Step-by-step explanation:
Answer: Distance between line and point =
4√5 -3/2√10
Step-by-step explanation:
Distance between the line is
= √ ((9-0)²+(0+1)²)
= √ (89+1)
= √90
= 3√10
Half of the line = 3/2√10
Distance of one side of the line and the point.
= √((9-1)²+(0-4)²)
= √((8)²+(-4)²)
=√64+16
= √80
= 4√5
Distance between line and point =
4√5 -3/2√10
Answer:
$212.5
Step-by-step explanation:
x= 100*170/80
x= 17000/80
x= 212.5