Given:
The perimeter of a rectangular building is 1200 feet.
The width of the building is 2 feet less than three times the length.
To find:
Width of the building.
Solution:
Let length of the building be x.
Then, width = 3x-2
We know that,
Add 4 on both sides
Divide both sides by 8.
Now,
Therefore, the width of the building is 449.5 feet.
1. BC is 1+3=4 (units)
2. AD is 3+5= 8 (units)
3. Draw the altitude CH from point C, as shown in the figure.
4. Then triangle CHD is a right triangle, with hypothenuse CD, and sides HD and CH.
5.
6. AB=CD=4.47 because the trapezoid is isosceles.
7. P= BC+AD+AB+CD=4+8+4.47+4.47=20.9 (units)
(n+5)^2=48
sqrt both sides
n+4=+/-4√3
minus 4 both sides
n=-4+/-4√3
-4+4√3>0 so this cannot be the value of n
n=-4-4√3
the number is -4-4√3
Answer:
154
Step-by-step explanation:
The vertical angles theorem states that vertical angles are congruent to each other. Since angles E and F are vertical angles, this means you can make them equal to each other in an equation.
m∠E = m∠F
17x + 1 = 20x - 14
Subtract 20x from both sides.
-3x + 1 = -14
Subtract 1 from both sides.
-3x = -15
Divide both sides by -3.
x = 5
Substitute 5 for x in m∠F (20x - 14).
20(5) - 14 = 86
m∠F = 86°
