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Pavlova-9 [17]
3 years ago
15

The perimeter of a rectangular building is 1200 feet. The width of the building is 2 feet less than three times the length. What

is the width of the building?
Mathematics
1 answer:
juin [17]3 years ago
6 0

Given:

The perimeter of a rectangular building is 1200 feet.

The width of the building is 2 feet less than three times the length.

To find:

Width of the building.

Solution:

Let length of the building be x.

Then, width = 3x-2

We know that,

Perimeter=2(length +width)

1200=2(x+3x-2)

1200=2(4x-2)

1200=8x-4

Add 4 on both sides

1204=8x

Divide both sides by 8.

\dfrac{1204}{8}=x

150.5=x

Now,

Width=3x-2

Width=3(150.5)-2

Width=451.5-2

Width=449.5

Therefore, the  width of the building is 449.5 feet.

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