f(x)=x-4f(3)=3-4so f(3)= -1
So I did this:
y=x +2
y=3x-4
I used the first equation to plug into the second equation.
x+2= 3x -4
I subtracted 3 from both sides so I get
-2x+2=-4
So I subtract 2 from both sides so I get
-2x=-6
I divide -2 on both sides and so I get
x=3
Then I plug the x into either equation. I did the first equation.
y=3+2
y=5
So x=3 and y=5
So legnt=l
width=w
l=-7+3w
l=3w-7
area=66
area=legnth times width or
area=lw
subisutte
area=lw
l=3w-7
66=(3w-7)(w)
66=3w^2-7w
subtrac 66 from both sides
0=3w^2-7w-66
factor
HOW TO
multiply 3 and -66=-198
find what 2 numbers add up to -7 and multiply to get -198
the numbers area 11 and -18
so
3w^2-18w+11w-66=0
factor
(3w^2-18w)+(11w-66)=0
(3w)(w-6)+(11)(w-6)=0
factor using distributive (ab+ac=a(b+c))
(3w+11)(w-6)=0
set them to zero
3w+11=0
subtract 11
3w=-11
legnths cannot be negative so we discard this
w-6=0
add 6
w=6
width=6
legnth=3w-7
length=3(6)-7
legnt=18-7
legnth=11
width=6
legnth=11
Answer:
c = 20 ft
Step-by-step explanation:
The largest square will be 14 sqrt(2) ft long
To figure out the side length of the square
use the pythagorean theorem
a^2 + b^2 =c^2
we are limited by the shortest side of the rectangle
28 ft
each side of the triangle is 1/2 the length of the short side of the rectangle or 14 ft
a^2 + b^2 =c^2
14^2 + 14^2 = c^2 where c is the side of the square
196 + 196 = c^2
392 = c^2
take the square root of each side
sqrt(392) = sqrt(c^2)
c = 14sqrt(2)
c = 19.799ft
to the nearest whole number
c = 20 ft
SOLUTION :-
AREA of sector = ( ∆/360° ) × πr²
∆ = given angle , r = radius
hence ,
AREA of sector for given angle
= ( 120°/360° ) × π 12² mi²
= ⅓ × π × 144 = 150.79 mi² = 151 mi² ( rounded off )
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