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GuDViN [60]
3 years ago
14

Exercice 2:

Mathematics
1 answer:
asambeis [7]3 years ago
8 0

Answer:

this question is wrong

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Can you help me solve x-1<-1 or 8x+9≥41
Elza [17]
For the first one:
x-1<span><-1
Add one on both sides.
x</span><span><0

For the second one:
8x+9</span><span>≥41
Subtract nine on both sides.
8x+</span><span>≥32
Divide by eight on both sides.
x</span><span>≥4

HOPE THIS HELPS YOU! ^_^</span>
3 0
3 years ago
Read 2 more answers
Express 20% as a decimal number
Oksanka [162]

Answer:

.20

Step-by-step explanation:

take the two digit % and move the decimal two places to the left

7 0
3 years ago
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What is the sum of r + s when r = –17.6 and s = 12.2? A. –29.8 B. –5.4 C. 5.4 D. 29.8
tankabanditka [31]
C. -5.4 -17.6+12.2= -5.4 because -17.6 goes first in the calculator but also its a negative
8 0
3 years ago
Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE
Viktor [21]

Answer:

<h2> (2, -1)</h2>

Step-by-step explanation:

Given the function f(x) = 8x³ − 12x² − 48x, <em>the critical point of the function occurs at its turning point i,e at f'(x) = 0</em>

First we have to differentiate the function as shown;

f'(x)= 3(8)x^{3-1}- 2(12)x^{2-1} - 48x^{1-1}\\  \\f'(x) = 24x^2 - 24x-48x^0\\\\f'(x) = 24x^2 - 24x-48\\\\At \ the\turning\ point\ f'(x)= 0\\24x^2 - 24x-48 = 0\\\\\\

Dividing \ through \ by \ 24\\\\x^2-x-2 = 0\\\\On \ factorizing\\\\x^2-2x+x-2 = 0\\\\x(x-2)+1(x-2) = 0\\\\(x-2)(x+1) = 0\\\\x-2 = 0 \ and \ x+1 = 0\\\\x = 2 \ and \ -1

Hence the critical numbers of the function are (2, -1)

8 0
3 years ago
Sixty less than ten times ten
Otrada [13]

Answer:

40

Step-by-step explanation:

10x10=100

100-60=40

Hope this helps! :)

3 0
3 years ago
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