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3 years ago

Use the coordinates of the labeled point to find a point-slope equation of the line.

Mathematics

1 answer:

DerKrebs [107]3 years ago

8 0

Answer:

(-2,-5) (0,-1)

(-1+5)/(0+2)= 4/2= 2

y + 5 = 2(x + 2)

y + 5 = 2x + 4

y = 2x - 1

Step-by-step explanation:

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What is a horizontal intercept on a graph

MaRussiya [10]

If you copy and paste this question on google, you get the answer. But sadly i can't copy and paste on here because it's plagiarism!<span />

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3 years ago

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Find the are of this compound shape below *

Alexandra [31]

Answer:

52 cm²

Step-by-step explanation:

First, we find the area of the bottom rectangle. We see it's 4 high and 10 wide, so 4x10 is 40. Then, we see that the small figure in the top right has a height of 4 and width of 3, so 4x3 = 12, add those and you get 52.

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3 years ago

It costs $120 for 20 students to visit an aquarium. How much does it cost for 152 students? Set up a proportion to solve.

nordsb [41]

Answer:

152 times 6=912

Step-by-step explanation:

$120 for every 20 students

it cost $6 for every 1 student

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3 years ago

at a particular high school, 42% of the students participate in sports and 25% of the students participate in drama. if 53% of t

baherus [9]

The probability that a student participates in both sports and drama is $0.14$ .

<h3>What is the formula for P(AUB), where A and B are any two events?</h3>

If $A$ and $B$ are any two events, then the probability of the joint event $(A\cup B)$ is given by the following formula: $P(A\cup B)=P(A)+P(B)-P(A\cap B)$

Given that 42% of the students participate in sports and 25% of the students participate in drama and 53% of the students participate in either sports or drama.

Suppose $S$ denotes that "a student participates in sports" and $D$ denotes that "a student participates in drama".
So, we have $P(S)=\frac{42}{100}=0.42$ , $P(D)=\frac{25}{100}=0.25$ , $P(S\cup D)=\frac{53}{100}=0.53$ .

We want to find the probability that a student participates in both sports and drama i.e., we want to find $P(S\cap D)$ .

By the above formula, we obtain:

$P(S\cup D)=P(S)+P(D)-P(S\cap D)\\\Longrightarrow P(S\cap D)=P(S)+P(D)-P(S\cup D)\\\Longrightarrow P(S\cap D)=0.42+0.25-0.53\\\therefore P(S\cap D)=0.14=\frac{14}{100}$

Therefore, the probability that a student participates in both sports and drama is $0.14$ .

To learn more about probability, refer: brainly.com/question/24756209

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1 year ago

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maxonik [38]

5% decrease 495/500= .95, 1.00-.95= .05

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3 years ago