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mote1985 [20]
3 years ago
8

Use the coordinates of the labeled point to find a point-slope equation of the line.

Mathematics
1 answer:
DerKrebs [107]3 years ago
8 0

Answer:

(-2,-5) (0,-1)

(-1+5)/(0+2)= 4/2= 2

y + 5 = 2(x + 2)

y + 5 = 2x + 4

y = 2x - 1

Step-by-step explanation:

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A triangular bandana has an area of 38 square inches. The height of the triangle is 9
meriva

Answer:

Base=8.4 inches

Step-by-step explanation:

Area of triangular bandana is 38sq inches

Height of triangle is 9 inches

Area of ∆ =½×b×h

38=½×b×9

38×2=b×9

76/9=b

b=8.4 inches

3 0
2 years ago
Why can you rewrite 4.7 as 4.70
N76 [4]
Because 4.7 is the "abbreviation" for 4.70 also 4.7 is the simplified version of 4.70 kind of like a fraction you 4 70/100 simplified is 4 7/10 or 4.7.
3 0
3 years ago
Read 2 more answers
Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10
zvonat [6]

The approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

<h3>What is depreciation?</h3>

Depreciation is to decrease in the value of a product in a period of time. This can be given as,

FV=P\left(1-\dfrac{r}{100}\right)^n

Here, (<em>P</em>) is the price of the product, (<em>r</em>) is the rate of annual depreciation and (<em>n</em>) is the number of years.

Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10%.

Suppose the original price of the first car is x dollars. Thus, the depreciation price of the car is 0.6x. Let the number of year is n_1. Thus, by the above formula for the first car,

0.6x=x\left(1-\dfrac{10}{100}\right)^{n_1}\\0.6=(1-0.1)^{n_1}\\0.6=(0.9)^{n_1}

Take log both the sides as,

\log 0.6=\log (0.9)^{n_1}\\\log 0.6={n_1}\log (0.9)\\n_1=\dfrac{\log 0.6}{\log 0.9}\\n_1\approx4.85

Now, the second car depreciates at an annual rate of 15%. Suppose the original price of the second car is y dollars.

Thus, the depreciation price of the car is 0.6y. Let the number of year is n_2. Thus, by the above formula for the second car,

0.6y=y\left(1-\dfrac{15}{100}\right)^{n_2}\\0.6=(1-0.15)^{n_2}\\0.6=(0.85)^{n_2}

Take log both the sides as,

\log 0.6=\log (0.85)^{n_2}\\\log 0.6={n_2}\log (0.85)\\n_2=\dfrac{\log 0.6}{\log 0.85}\\n_2\approx3.14

The difference in the ages of the two cars is,

d=4.85-3.14\\d=1.71\rm years

Thus, the approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

Learn more about the depreciation here;

brainly.com/question/25297296

4 0
2 years ago
Which values of x and y are solutions to the open sentence?       4y ≥ 3x + 2   A. x = 3, y = 0   B. x = 4, y = 3   C. x = 6, y
kobusy [5.1K]
Your answer would be C. x = 6, y = 5
This is because if you plug the numbers in to the inequality, we get:
(4 × 5) ≥ (3 × 6) + 2
20 ≥ 18 + 2
20 ≥ 20
which is correct.

I hope this helps!
5 0
3 years ago
Read 2 more answers
HELP ME WITH NUMBER 1 PLEASE!!!!!
Sonja [21]

Answer:

x > 367

Step-by-step explanation:

set x = # of DVDs they sold

Each DVD costs $15 so the total amount they made is 15x

Since they raised more than $5500

15x > 5500

Divide both sides by 15 to solve the inequality and you get

x > 366.67 and since you can't sell 0.67 of a DVD, round up to get

x > 367 which means that they sold more than 367 DVDs

8 0
3 years ago
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