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2 years ago

rmula1" title="If w=2x, then \int\limits^2_0 {f(2x)} \, dx =" alt="If w=2x, then \int\limits^2_0 {f(2x)} \, dx =" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

elena-14-01-66 [18.8K]2 years ago

8 0

First, you should solve for $f(2x)$ , which equals $2*(2x)=4x$ . Now, solve the integral of $f(2x)$ = $2*(2x)=4x$ , to get that $\int\ {(f(2x)=4x)} \, dx= 2x^2$ . You can check this by taking the integral of what you got. Now by the Fundamental Theorem $\int\limits^2_0 {4x} \, dx=[2x^2] ^{2}_{0}=2(2)^{2}-2(0)^2=8$ .

This should be the answer to your question, if I understood what you were asking correctly.

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What would the answer be

Hoochie [10]

Answer:

Step-by-step explanation:

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4 0

3 years ago

Marcie bought a total of 20 used books and cds during a yard sale for a total of 54.50$. of books cost 1.50$ each and cds 5$ eac

melomori [17]

Let numbers of books be 'b' and numbers of CDs be 'c'

We can set up two equations:
Equation [1] ⇒ $b+c=20$
Equation [2] ⇒ $1.50b+5c=54.50$

We are solving for the number of books and the number of CDs bought

When we have two equations in terms of two different variables; $b$ and $c$ , that we need to solve, then this becomes a simultaneous equation problem.

First, rearrange Equation [1] to make either $b$ or $c$ the subject:
$b+c=20$
$b=20-c$

Then we substitute $b=20-c$ into Equation [2]
$1.50b+5c=54.50$
$1.50(20-c)+5c=54.50$
$30-1.50c+5c=54.50$
$5c-1.5c=54.50-30$
$3.5c=24.50$
$c=7$

Now we know the value of $c$ which is $c=7$ , substitute this value into $b=20-c$ we have $b=20-7=13$

Answer:
Numbers of books = 13
Numbers of CDs = 7

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3 years ago

its first year of operation Big Lake Camp had 40 campers this year the tents was under 80% of the first year how many campers pa

Irina18 [472]

Answer:
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Step-by-step explanation:
you would have to multiply the percent to the amount of campers in Big Lake Camp in the first year:
40(1.8) = 72

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2 years ago

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Step-by-step explanation:

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3 years ago

For a right triangle that has legs a and b and hypotenuse c, find the lengt h of the side not given here a-1 c= square root of 3

denis-greek [22]

Use the Pythagorean theorem:
$c^2=a^2+b^2$
We have:
$a=1;\ c=\sqrt3$
Substitute:
$1^2+b^2=(\sqrt3)^2\\\\1+b^2=3\ \ \ |-1\\\\b^2=2\to b=\sqrt2$
<span>We calculate the area of the triangle by two methods:</span>
$A_\Delta=\dfrac{ab}{2}\ and\ A_\Delta=\dfrac{ch}{2}$

$\dfrac{h\sqrt3}{2}=\dfrac{1\sqrt2}{2}\ \ \ \ |\cdot2\\\\h\sqrt3=\sqrt2\ \ \ |\cdot\sqrt3\\\\3h=\sqrt6\ \ \ |:3\\\\h=\dfrac{\sqrt6}{3}$
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3 years ago