If a quadrilateral is a rhombus then:
i) all its sides have equal length,
and
ii) the 2 diagonals are perpendicular and bisect each other.
The 2 diagonals of rhombus JKLM intersect at N.
Then m(MNJ)=90°, |JN|=4 and |NM|=3 units
thus, by the Pythagorean theorem,

The perimeter of the rhombus is 4*5 units=20 units.
Answer: 20 units
Answer:
28 and 30
Step-by-step explanation:
'x' = 1st consecutive #
'x+2' = 2nd consecutive #
x + x+2 = 58
2x + 2 = 58
2x = 56
x = 28
x+2 = 30
56
28 2
14 2 | 2
7 2 | 2 | 2
or
56
14 4
7 2 | 2 2
Let's rewrite the expression as

So, if
, you may divide both sides by
, the equation becomes
, and the only solution is
, which means that this is not an identity (an indentity is tautologically true, no matter the value of x).
If instead
, you are multiplying both sides by zero, so the equation becomes

So, it doesn't matter which value for x you choose, because you will always end up with
, which is obviously always true.