√(36g^6) = 6g^3 . . . . a simpler form
Answer:
≈ 58
Step-by-step explanation:
Estimation usually means you want an answer good to one or maybe two significant figures. That usually means you want to round the numbers involved to one or two significant figures.
Doing that here transforms the problem to 180/3 = 60, an answer with one significant figure.
You can improve the estimate a bit by recognizing that it is a little high (the numerator is higher than 175.32, but the denominator is the same). Since the numerator is high by about 5, the estimate is high by about 5/3 or a little less than 2. A closer estimate will be 60 - 2 = 58.
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The degree to which you refine the estimate will depend on the error requirements you have. Certainly an estimate of 60 is within 10% of the true value, so is "close enough" for many purposes.
Let us say ,
x=number of students who passed
y=number of students who failed
total number of students =276
x+y=276..................(1)
We are given 5 times the number of students passed as failed.
x=5y.............(2)
plugging value of x from (2) in (1),
5y+y=276
6y=276
y=46
x=5y=46*5=230
x=number of students who passed=230
Answer:
a = 16
Step-by-step explanation:
4/8= 1/2
you have to what 8 is half of
8×2= 16
a=16
A. Area is length times width so it would be
3*5=15
15ft^2
B. 3*10=30
30+15= 45
45ft^2 when pushed together
C. 54-45=9
Table three has an area of 9ft^2
