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Rama09 [41]
3 years ago
5

−1w + 4w4 + y4 – 3y4 – 2w – 3w4

Mathematics
1 answer:
vlabodo [156]3 years ago
3 0
-w + 4w⁴ + y⁴ - 3y⁴ - 2w - 3w⁴
-w - 2w + 4w⁴ - 3w⁴ + y⁴ - 3y⁴
-3w + w⁴ - 2y⁴
w⁴ - 2y⁴ - 3w
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HELP PLS NEED HELP <br> IF U KNOW THE ANSWER PLS HELP
steposvetlana [31]
Square the -5 then use substitution (just combine the numbers)

5 0
3 years ago
An airplane flies due north from ikeja airport for 500km.It then flies on a bearing of 060 from a further distance of 300km befo
Nata [24]

Answer:

482 km

63.94 degrees

Step-by-step explanation:

to solve this question we will use the cosine rule. For starters, draw your diagram. From point A, up north is 500km and 060 from there, another 300. If you join the point from the road junction back to the starting point, yoou have a triangle.

Cosine rule states that

C = \sqrt{A^{2} + B^{2} -2AB   cos(c)  }

where both A and B are the given distances, 500 and 300 respectively, C is the 3rd distance we're looking for and c is the given angle, 060

solving now, we have

C = \sqrt{500^{2} + 300^{2} -2 * 500 * 300 cos(60)  }

C = \sqrt{250000 + 90000 - [215000   cos(60)  }]

C = \sqrt{340000 - [215000 * 0.5  }]

C = \sqrt{340000 - [107500  }]

C =\sqrt{232500}

C = 482 km

The bearing can be gotten by using the Sine Rule.

\frac{sina}{A} = \frac{sinc}{C}

sina/500 = sin60/482

482 sina = 500 sin60

sina = \frac{500 sin60}{482}

sina = 0.8983

a = sin^-1(0.8983)

a = 63.94 degrees

6 0
3 years ago
1. y = x2 + 8x + 15<br> Find the zeros of the function by rewriting the function in intercept form
lubasha [3.4K]

The zeros of given function y=x^{2}+8 x+15 is – 5 and – 3

<u>Solution:</u>

\text { Given, equation is } y=x^{2}+8 x+15

We have to find the zeros of the function by rewriting the function in intercept form.

By using intercept form, we can put value of y as  to obtain zeros of function

We know that, intercept form of above equation is x^{2}+8 x+15=0

\text { Splitting } 8 x \text { as }(5+3) x \text { and } 15 \text { as } 5 \times 3

\begin{array}{l}{\rightarrow x^{2}+(5+3) x+5 \times 3=0} \\\\ {\rightarrow x^{2}+5 x+3 x+5 \times 3=0}\end{array}

Taking “x” as common from first two terms and “3” as common from last two terms

x (x + 5) + 3(x + 5) = 0

(x + 5)(x + 3) = 0

Equating to 0 we get,

x + 5 = 0 or x + 3 = 0

x = - 5 or – 3

Hence, the zeroes of the given function are – 5 and – 3

5 0
3 years ago
I will give brainliest, if it is right, and you are the first person to answer.
sertanlavr [38]

Answer:47.25

Step-by-step explanation: it is 10.5 x the 4.5

7 0
3 years ago
Read 2 more answers
Jim currently has​ $1,250 in his bank account and Sally has​ $1,400 in her bank account. Jim deposits​ $27.50 per week and Sally
Paha777 [63]

Answer:

20 weeks

Explanation: this is the answer

3 0
3 years ago
Read 2 more answers
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