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4 years ago

A proportion is an equation that states two _____ are equal.

Mathematics

2 answers:

BlackZzzverrR [31]4 years ago

6 0

A proportion<span> is a name we give to a statement that two ratios are equal. It can be written in two ways

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Dafna1 [17]4 years ago

5 0

Proportions have two fractions so the answer is ratios.

Hope it helps :)

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Is 2 greater or less than or equal to -5?

Marina CMI [18]

2 is greater then -5.

2 is a positive number unlike -5 it is a negative which is less then 2.

5 0

3 years ago

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Identify the functions that are continuous on the set of real numbers and arrange them in ascending order of their limits as x t

Studentka2010 [4]

Answer:

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

Step-by-step explanation:

1. $f(x)=\frac{x^2+x-20}{x^2+4}$

The denominator of f is defined for all real values of x

Therefore, the function is continuous on the set of real numbers

$\lim_{x\rightarrow 5}\frac{x^2+x-20}{x^2+4}=\frac{25+5-20}{25+4}=\frac{10}{29}=0.345$

3. $h(x)=\frac{3x-5}{x^2-5x+7}$

$x^2-5x+7=0$

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function h is defined for all real values.

$\lim_{x\rightarrow 5}\frac{3x-5}{x^2-5x+7}=\frac{15-5}{25-25+7}=\frac{10}{7}=1.43$

2. $g(x)=\frac{x-17}{x^2+75}$

The denominator of g is defined for all real values of x.

Therefore, the function g is continuous on the set of real numbers

$\lim_{x\rightarrow 5}\frac{x-17}{x^2+75}=\frac{5-17}{25+75}=\frac{-12}{100}=-0.12$

4. $i(x)=\frac{x^2-9}{x-9}$

x-9=0

x=9

The function i is not defined for x=9

Therefore, the function i is not continuous on the set of real numbers.

5. $j(x)=\frac{4x^2-7x-65}{x^2+10}$

The denominator of j is defined for all real values of x.

Therefore, the function j is continuous on the set of real numbers.

$\lim_{x\rightarrow 5}\frac{4x^2-7x-65}{x^2+10}=\frac{100-35-65}{25+10}=0$

6. $k(x)=\frac{x+1}{x^2+x+29}$

$x^2+x+29=0$

It cannot be factorize .

Therefore, it has no real values for which it is not defined .

Hence, function k is defined for all real values.

$\lim_{x\rightarrow 5}\frac{x+1}{x^2+x+29}=\frac{5+1}{25+5+29}=\frac{6}{59}=0.102$

7. $l(x)=\frac{5x-1}{x^2-9x+8}$

$x^2-9x+8=0$

$x^2-8x-x+8=0$

$x(x-8)-1(x-8)=0$

$(x-8)(x-1)=0$

$x=8,1$

The function is not defined for x=8 and x=1

Hence, function l is not defined for all real values.

8. $m(x)=\frac{x^2+5x-24}{x^2+11}$

The denominator of m is defined for all real values of x.

Therefore, the function m is continuous on the set of real numbers.

$\lim_{x\rightarrow 5}\frac{x^2+5x-24}{x^2+11}=\frac{25+25-24}{25+11}=\frac{26}{36}=\frac{13}{18}=0.722$

g(x)<j(x)<k(x)<f(x)<m(x)<h(x)

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3 years ago

A 91 square foot bathroom has a length of 13 feet. what is the width of the bathroom

Radda [10]

<span>The answer is 7 ft. The bathroom has rectangular shape. The area (A) of a rectangle is the product of the width (w) and length (l): A = w * h. The bathroom is rectangular. We know that A = 91 ft^2 and l = 13 ft. Let's substitute them in the formula for the area: 91 ft^2 = w * 13 ft. w = 91 ft^2 : 13 ft. w = 7 ft. The width of the bathroom is 7 ft.Hope this helps. Let me know if you need additional help!</span>

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3 years ago

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What is the answer to 1/9 + 3/5

hjlf

32/45 is the answer I believe

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3 years ago

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HELP I DONT KNOW THESE :(

Leya [2.2K]

The answer is -1 and 2

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3 years ago