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2 years ago

6 = 2(1+2) = Somebody help me answer this please

Mathematics

2 answers:

Ymorist [56]2 years ago

4 0

Answer:

6 = 6 This statement is true.

Step-by-step explanation:

First you want to distribute the 2 into the 1 and 2.

6 = 2 + 4

Add.

6 = 6

This is true.

Kitty [74]2 years ago

3 0

Answer:

Step-by-step explanation:

6 = 2(1+2)

Use distributive property (Multiply 2 and 1. Then multiply 2 and 2)

6 = 2+4

Now add

6=6

This means the statement is true

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What is the largest number of consecutive integers whose sum is 2003?

Sladkaya [172]

$2003 \div 2$ =1001.5

Go .5 below and .5 above this answer to get your consecutive integers.

Therefore the answer is 1001 and 1002.

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3 years ago

A student has gotten the following grades on his tests. What is the minimum grade he must get on the last test in order to have

klemol [59]

Answer:

Step-by-step explanation:

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2 years ago

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zavuch27 [327]

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Step-by-step explanation:

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3 years ago

Read 2 more answers

Write in radical form

Studentka2010 [4]

Step-by-step explanation:

I'll do one for you.

Using the formula for turning exponents into radicals

$(b) {}^{ \frac{x}{y} } = \sqrt[y]{b} {}^{x}$

where b is the base

This means that the numerator in the exponet form becomes the power under the radical in radical form and

the denominator in exponet form becomes the nth root in radical form.

For example 5,

$(5) {}^{ \frac{ - 3}{5} }$

That becomes in radical form

$\sqrt[5]{5 {}^{ - 3} }$

or if you want to write it using positive exponents

$\frac{1}{ \sqrt[5]{5 {}^{3} } }$

I'll do one more for you

For example 6,

$11 {}^{ \frac{4}{3} }$

That becomes in radical form

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3 years ago

Simplify sin q + cosq cotq.

IRINA_888 [86]

$\sin q+\cos q\cot q=\sin q+\cos q\cdot\dfrac{\cos q}{\sin q}=\sin q+\dfrac{\cos^2q}{\sin q}\\\\=\dfrac{sin^2q}{\sin q}+\dfrac{\cos^2q}{\sin q}=\dfrac{\sin^2q+\cos^2q}{\sin q}=\dfrac{1}{\sin q}=\csc q\\\\Used:\\\cot q=\dfrac{\cos q}{\sin q}\\\\\sin^2q+\cos^2q=1\\\\\csc q=\dfrac{1}{\sin q}$

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3 years ago