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3 years ago

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Mathematics

1 answer:

zavuch27 [327]3 years ago

4 0

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Find the gradient of the line segment between the points (10,-4) and (6,-16).

svet-max [94.6K]

The answer is -3 . Use the gradient formula y2-y1/x2-x1

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2 years ago

Please help me with this question... please

alina1380 [7]

Pretty sure it’s the fourth option

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3 years ago

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The blueprint for a new swimming pool uses the scale 3/4

beks73 [17]

Answer:

3 in wide by 4.5 in long.

Step-by-step explanation:

3/4=0.75

I divided the given dimensions by two, so I could multiply .75 by the sets of twos instead of dividing 3/4 by two and multiplying that by 12 and 8.

.74 x 4 = 3

.75 x 6 = 4.5

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3 years ago

Write the standard form of the line with the given information. Include your work in your final answer. Type your answer in the

AURORKA [14]

Answer:

The standard form of line is

$-3x+y=-2$

Step-by-step explanation:

we are given a line

slope=3

so,

$m=3$

y-intercept of -2

so,

$b=-2$

now, we can use slope-intercept form of line

$y=mx+b$

now, we can plug values

$y=3x-2$

we can write it in standard form of line

$ax+by=c$

$y=3x-2$

we can subtract both sides by 3x

$y-3x=3x-2-3x$

$y-3x=-2$

$-3x+y=-2$

So, the standard form of line is

$-3x+y=-2$

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3 years ago

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Find the 59th term of the following arithmetic sequence. 15, 23, 31, 39

m_a_m_a [10]

$15~~,~~\stackrel{15+8}{23}~~,~~\stackrel{23+8}{31}~~,~~\stackrel{31+8}{39}~~,~~...~\hspace{10em}\stackrel{common~difference}{d=8} \\\\[-0.35em] ~\dotfill\\\\ n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} a_n=n^{th}\ term\\ n=\stackrel{\textit{term position}}{59}\\ a_1=\stackrel{\textit{first term}}{15}\\ d=\stackrel{\textit{common difference}}{8} \end{cases} \\\\\\ a_{59}=15+(59-1)8\implies a_{59}=15+472-8\implies a_{59}=479$

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3 years ago