(1.02(1.02(1.02(1.02(1500))))) = 1623.64
1623 deer after 4 years
Height of the woman = 5 ft
Rate at which the woman is walking = 7.5 ft/sec
Let us assume the length of the shadow = s
Le us assume the <span>distance of the woman's feet from the base of the streetlight = x
</span>Then
s/5 = (s + x)/12
12s = 5s + 5x
7s = 5x
s = (5/7)x
Now let us differentiate with respect to t
ds/dt = (5/7)(dx/dt)
We already know that dx/dt = 7/2 ft/sec
Then
ds/dt = (5/7) * (7/2)
= (5/2)
= 2.5 ft/sec
From the above deduction, it can be easily concluded that the rate at which the tip of her shadow is moving is 2.5 ft/sec.
I did
14/3=4 2/3
so the final answer is 4 and 2/3
0.000576 is the right awnser
Answer
N = 32 ÷ (5 - 1)
N = 32 ÷ 4
N =8
Step-by-step explanation:
