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eduard
3 years ago
14

If a > 0 and b < 0, then which of the following must be true.

Mathematics
1 answer:
slava [35]3 years ago
7 0
<span>We need to find the correct answer on the given choices:

If a > 0 and b < 0, then The answer is a + b > 0
let’s give a specific example:
let’s have a = 1
and b = .20

</span> <span>Now, let’s try calculating if our answer is correct.
Thus a + b > 0
=> a + b
=> 1 + .20
=> 1.20
and 1.20 is greater than 0.
=>Therefore 1.20 > 0 = a + b > 0</span>



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Hailey took a taxi from her house to the airport. The taxi company charged a pick-up fee of $2.40 plus $4.50 per mile. The total
Annette [7]

Answer:

The taxi drove Hailey for 19 miles.

Step-by-step explanation:

1. Subtract the tip.

$87.90 - $2.40 = $85.5

2. Divide by the price per mile. ($4.50)

$85.5 / $4.50 = 19

8 0
3 years ago
Find the mean,median,mode and,range of the following data set 18 12 14 12 16 24 18 12 14
devlian [24]

Answer:

Mean = 15.5

Median = 14

Mode = 12

Range = 12

Step-by-step explanation:

The mean is the sum of all the values divided by the number of values.

So mean = S/N.

There are 9 values, so N = 9.

These values are 18,12,14,12,16, 24,18,12,14. So S = 18+12+14+12+16+24+18+12+14 = 140

Mean = 140/9 = 15.5

-------------------------------------------------------------------------------

For the median, the first step is to sort all the elements in a crescent way.

So 12 12 12 14 14 16 18 18 24

Then you will need to consider whether N is even or odd.

If N is even, to find the median you need to sum the values at the positions N/2 and (N/2)+1 and divide by 2.

In this case, N is odd. So the median will be the value at the position (N+1)/2, which is 14.

--------------------------------------------------------

The mode is the value that appears most often in a set. In this set, 12 appears 3 times, 14 and 18 appears twice and while 12 and 13 appear once each. So the mode is 12.

--------------------------------

The range of a set is:

Highest value - Smallest Value

In this set: range = 24-12 = 12

4 0
3 years ago
Ten plus eight times a number a equals eleven times another number d minus six solve for a
svet-max [94.6K]
So your equation would be 8a+10=11d-6 First: you would combine like terms so normally you would take away the smaller number. So to cancel out the negative 6 you added you add positive six to the negative 6 so you would get 0 and whatever you do to one side you have to do to the other so you would do 10 + 6. Your new equation would be 8a+16=11d. Now you do -16 to both sides. So your new equation would be 8a= 11d - 16. Now you divide by 8. So your final equation would be a=11d-2.
8 0
3 years ago
Read 2 more answers
Jamie went to Home Depot.She bought 25 bags of soil that cost $9 per bag.She bought 15 pots at $8 each, and she bought 23 bags o
Anna71 [15]

Answer:

Im pretty sure it is $660

Step-by-step explanation:

(25x9)+(15x8)+(23x15)=

225+120+345= 690

690-(6x5)

690-30

[660]


3 0
4 years ago
Let us analyze the following setting. You are given a circle of unit circumference. You pickkpoints on the circle independently
garik1379 [7]

Answer:

We have been given a unit circle which is cut at k different points to produce k different arcs. Now we can see firstly that the sum of lengths of all k arks is equal to the circumference:

\small \sum_{i = 1}^{k} L_i= 2\pi

Now consider the largest arc to have length \small l . And we represent all the other arcs to be some constant times this length.

we get :

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where C(i) is a constant coefficient obviously between 0 and 1.

\small \sum_{i = 1}^{k} C_i= 2\pi/l

All that I want to say by using this step is that after we choose the largest length (or any length for that matter) the other fractions appear according to the above summation constraint. [This step may even be avoided depending on how much precaution you wanna take when deriving a relation.]

So since there is no bias, and \small l may come out to be any value from [0 , 2π] with equal probability, the expected value is then defined as just the average value of all the samples.

We already know the sum so it is easy to compute the average :

\small L_{Exp} = \frac{2\pi}{k}

7 0
3 years ago
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