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Lelechka [254]
3 years ago
9

Can someone help me out

Mathematics
1 answer:
LenKa [72]3 years ago
4 0

Answer:(y_2-y_1)/(x_2-x_1 )

Step-by-step explanation:

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3 years ago
An observer, whose eyes are 1.98 m above the ground, is standing 39.2 m away from a tree. The ground is level, and the tree is g
lozanna [386]

Answer:

The tree is 16.25 m tall.

Step-by-step explanation:

Attached is a diagram that better explains the problem.

From the diagram we see that the distance between the top of the tree and the line of sight of the observer is x.

To find the height of the tree, we need to first find x and then add it to the height of the observers line of sight from the ground.

Using SOHCAHTOA trigonometric function:

tan(20) = x/39.2

=> x = 39.2 * tan(20)

x = 39.2 * 0.364

x = 14.27m

Hence, the height of the tree is:

(14.27 + 1.98)m

16.25m

The tree is 16.25 m tall.

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3 years ago
Find the Surface Area of the right triangular prism.
Elis [28]
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2 years ago
Quadrilateral ABCD has vertices A(-3, 4), B(1, 3), C(3, 6), and D(1, 6). Match each set of vertices of quadrilateral EFGH with t
Rasek [7]

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The table represents some points on the graph of a linear function.
Sunny_sXe [5.5K]

Answer:

B. -\frac{9}{2}

Step-by-step explanation:

Rate of change of y with respect to x, can be calculated using any two of the pairs of values of the table, say, (-2, 12) and (0, 3).

Rate of change = \frac{y_2 - y_1}{x_2 - x_1}

Let,

(-2, 12) = (x_1, y_1)

(0, 3) = (x_2, y_2)

Plug in the values

Rate of change = \frac{3 - 12}{0 - (-2)} = \frac{-9}{2} = -\frac{9}{2}

7 0
2 years ago
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