Answer:
y = 1/6 x^2 + 8/3 x + 49/6
Step-by-step explanation:
This is a parabola which opens upwards.
The distance of a point (x, y) from the focus is
√[(x - -8)^2 + (y - -1)^2] and
the distance of the point from the line y = -4
= y - -4
These distances are equal for a parabola so:
√[(x - -8)^2 + (y - -1)^2] = y + 4
Squaring both sides:
(x + 8)^2 + (y + 1)^2 = (y + 4)^2
x^2 + 16x + 64 + y^2 + 2y + 1 = y^2 + 8y + 16
x^2 + 16x + 64 + 1 - 16 = 8y - 2y
6y = x^2 + 16x + 49
y = 1/6 x^2 + 8/3 x + 49/6 is the equation of the parabola.
A 12-sided die is rolled. The set of equally likely outcomes is {1,2,3,4,5,6,7,8,9,10,11,12). Find the probability of rolling a
levacccp [35]
Answer:
![P(x>12) = 0](https://tex.z-dn.net/?f=P%28x%3E12%29%20%3D%200)
Step-by-step explanation:
Given
--- outcomes
-- sample size
Required
![P(x > 12)](https://tex.z-dn.net/?f=P%28x%20%3E%2012%29)
This is calculated as:
![P(x > 12) = \frac{n(x > 12)}{n(x)}](https://tex.z-dn.net/?f=P%28x%20%3E%2012%29%20%3D%20%5Cfrac%7Bn%28x%20%3E%2012%29%7D%7Bn%28x%29%7D)
because none of the outcomes is greater than 12:
So:
![P(x > 12) =\frac{0}{12}](https://tex.z-dn.net/?f=P%28x%20%3E%2012%29%20%3D%5Cfrac%7B0%7D%7B12%7D)
![P(x>12) = 0](https://tex.z-dn.net/?f=P%28x%3E12%29%20%3D%200)
A scale of 8cm:12cm would be a scale of 2/3. since this is the case, we can divide the scale drawing of the playground by the scale factor to get the length of the actual playground
12.4/0.6666 = 18.6
The answer is 18.6
Sry but I need more information to answer the question. So so sry!