Question

What is the amplitude and period of f(t)= -cos 3t?

Answer 1

Answer:

c. The amplitude is 1.

The period is $\frac{2\pi}{3}$

Step-by-step explanation:

The given cosine function is ;

$f(t)=-\cos 3t$

This function is of the form;

$f(t)=a\cos bt$

The amplitude is given by |a|

|-1|=1

The period of this function is given by;

$T=\frac{2\pi}{|b|}$

$T=\frac{2\pi}{|3|}=\frac{2\pi}{3}$

The amplitude is 1.

The period is $\frac{2\pi}{3}$

Answer 2

Answer:

option c

amplitude 1 ; period 2π/3

Step-by-step explanation:

Given in the question a function,

f(t)=-cos3t

Standard form of cosine function is

f(t)=acos(bt)

Amplitude is given by = |a|

Period of function is given by = 2π/b

So the amplitude is |-1| = 1

    the period is 2π/3 = 2π/3