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TiliK225 [7]
3 years ago
6

What is the slope of line a

Mathematics
2 answers:
Crazy boy [7]3 years ago
5 0
The answer is 1/3. M=1/3
Cerrena [4.2K]3 years ago
4 0

Answer:

-1/3

Step-by-step explanation:

It is -1/3 because your going down and its like going underground and the grass is the 0-line then anything lower is a -x number if you were going up the "slope" then it would be a positive number.

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-5x - 35= -15<br> -5x = 25<br> X =
Zigmanuir [339]
X= -5 because you divide -5x by -5 to get x alone so you have to 25/-5 which is -5
3 0
3 years ago
David is thinking about getting the new Iphone. He has to pay a fee up front and also a recuring monthly charge until the
TiliK225 [7]

Answer:

tell him tell him dphones are trash and slow

Step-by-step explanation:

5 0
3 years ago
What equation is graphed in this figure?
Ksivusya [100]

to get the equation of any straight line, we simply need two points off of it, let's use those two points in the picture below.

(\stackrel{x_1}{0}~,~\stackrel{y_1}{2})\qquad (\stackrel{x_2}{1}~,~\stackrel{y_2}{5}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{5}-\stackrel{y1}{2}}}{\underset{run} {\underset{x_2}{1}-\underset{x_1}{0}}}\implies \cfrac{3}{1}\implies 3 \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_2=m(x-x_2) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_2}{5}=\stackrel{m}{3}(x-\stackrel{x_2}{1})

keeping in mind that for the point-slope form, either point will do, in this case we used the second one, but the first one would have worked just the same.

7 0
1 year ago
Please help! Limits. Just confirm that an coverages to 2 as n--&gt;infinity
Alexxandr [17]

Answer:

Limit is 2

Step-by-step explanation:

The last term approaches zero as n approaches infinity so the fuction approaches 2.

7 0
3 years ago
I need help how do I slove this and how do I figure out the ratio. And could you provide a guide on how you go about finding the
bulgar [2K]

Answer:

<h3>Option C. 6 : 1 is the answer.. </h3>

<h2>Hope it can help you and please mark me as a brainlist..</h2>
7 0
2 years ago
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