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Drupady [299]
3 years ago
14

24 students and Jamal's class are wearing tennis shoes there are 30 students in this class your mom says that 70% of this class

is wearing tennis shoes is the Jamal correct
Mathematics
1 answer:
mel-nik [20]3 years ago
3 0
Im not sure if i am understanding the question correctly... 

If you are asking if Jama's mom is correct, then no. she is wrong. this is because 

if you take the proportion,  (is/of)=(%/100) you get (x/30)=(70/100). You then solve for x which in this case would be 21 students are wearing tennis shoes.

Hope this helps. 
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verify that the fucntion satisfies the three hypotheses of rolles theorem on the given interval . then find all numbers c that s
Ghella [55]

The roots of the polynomial <span><span>x^3 </span>− 2<span>x^2 </span>− 4x + 2</span> are:

<span><span>x1 </span>= 0.42801</span>

<span><span>x2 </span>= −1.51414</span>

<span><span>x3 </span>= 3.08613</span>


x1 and x2 are in the desired interval [-2, 2]

f'(x) = 3x^2 - 4x - 4

so we have:

3x^2 - 4x - 4 = 0

<span>x = ( 4 +- </span><span>√(16 + 48) </span>)/6

x_1 = -4/6 = -0.66

x_ 2 = 2

According to Rolle's theorem, we have one point in between:

x1 = 0.42801 and x2 = −1.51414

where f'(x) = 0, and that is <span>x_1 = -0.66</span>

so we see that Rolle's theorem holds in our function.

4 0
3 years ago
Help plea i am beg screenshot in
stiv31 [10]

Answer:

SA = 105 in^2

Step-by-step explanation:

To find surface area, find the area of all the shapes and add it all together. This shape has 4 triangle faces. They are all the same. So we can find one of them and times by 4.

Area of a triangle:

A = 1/2b•h

= 1/2• 5 • 8

= 1/2 • 40

= 20

One triangle has area 20, so times by 4 (bc four triangles)

4•20

= 80

Area of square 5•5

= 25

Add the areas:

80 + 25

= 105 sq in

7 0
2 years ago
Can you please explain how to write the ratios for sin x and cos x? When angles are x, y, and z. The hypotenuse being 12 and is
Kamila [148]
Your triangle has acute angles X and Y, and right angle Z.

For an acute angle A in a right triangle:

The sine is the ratio of the opposite leg to the hypotenuse.
sin A = opp/hyp

The cosine is the ratio of the adjacent leg to the hypotenuse.
cos A = adj/opp

The hypotenuse of a right triangle is the side opposite the right angle. It is the longest side of a right triangle. There is only one hypotenuse in a triangle, so there is no confusion with the hypotenuse.

The two sides that form the right angle are called the legs. Each leg is opposite an acute angle. The legs may or may not be congruent to each other, but each leg is always shorter than the hypotenuse. Since there are two legs, we need to be able to distinguish them. If you take an acute angle as your angle of interest, the leg that is part of the angle is called the adjacent leg. The other leg is the opposite leg. Adjacent leg and opposite leg are relative terms. They depend on the acute angle you are considering.

For your triangle, if you look at angle X, then the adjacent leg is side XZ. The opposite leg for angle X is side YZ.

Using the ratios mentioned above for sine and cosine, you get:

sin X = opp/hyp = sqrt(119)/12

cos X = adj/hyp = 5/12
7 0
3 years ago
Sketch the graph of the inequality.<br> 9. 7y − 2x + 3 &lt; 17
ohaa [14]

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Natasha2012 [34]
<span>The missing angle measure in triangle ABC is 55°.

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Triangles ABC and DEF are similar by the angle-angle criterion. 
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5 0
3 years ago
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