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ki77a [65]
3 years ago
14

For a resistor in a direct current circuit that does not vary its resistance, the power that a resistor must dissipate is direct

ly proportional ti the square of the voltage across the resistor. The resistor must dissipate 1/16 watt of power when the voltage across the resistor is 14 volts. Find the power that the resistor must dissipate when the voltage across it is 42 volts.
Mathematics
1 answer:
Mrrafil [7]3 years ago
6 0

THe problem is basically telling us: P=kV^2

where P is the power disappated and V^2 is our voltage squared.

\frac{1}{16}=k*14^2\implies\\ \frac{1}{16*196}=k \implies \\ \frac{1}{3136}=k

So, for the second example to find the power we simply have to plug k and our voltage back in, so:P=\frac{14^2*3^2}{14^2*6} \implies \\ P=\frac{9}{6}= \frac{3}{2}

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1) original table of values:


x      1     2     3    4    5

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3) So, the table of values of the inverse of the given function is:


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Answer:

∠ ABD = 42°

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